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3 years ago

Clouds absorb outgoing radiation emitted by Earth and retaliate a portion of it back to the surface during....

Physics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

A. Night time

Explanation:

During day time, when the sun rays fall on surface of Earth, major amount of rays are reflected back to upper atmosphere but some energy is absorbed by the surrounding.

This energy trapped in clouds and earth surrounding helps to maintain the temperature on surface during the night hours.

This trapped energy which is radiated by clouds is very important for the balanced temperature.

Ilia_Sergeevich [38]3 years ago

4 0

A - Night time

They do this as the atmosphere tends to cool during the night

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A meteor moving through outer space continues to move on the same path until an outside force acts on it

Fittoniya [83]

Newton stated 3 laws that rules moving bodies:

First law - an object remains in its state (resting or moving at constant speed) unless acted upon a force

Second law - the force (F) of an object is equal to its mass (m) multiplied by its acceleration (a); F = m x a

Third law - when an object exerts a force upon another, the second object exerts a force that is equal in magnitude and opposite in direction

So, according to the First Law of Motion, the metor moving through outer space will continues its motion until an outside force acts upon it

6 0

3 years ago

Read 2 more answers

Which of the following represents a heterygous genotype? A-YY B-yy C-Y^H Y^H D-Yy

Fofino [41]

The only one with two different alleles is d meaning it is heterozygous

D

3 0

3 years ago

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 49 m in front of you. You reaction time

Leno4ka [110]

Answer:

v = 26.7 m/s

Explanation:

Given,

speed of the car = 20 m/s

distance between the car and the deer = 49 m

time taken to press the brake = 0.50 s

maximum deceleration of the car = 10 m/s²

Now,

distance travel by the car in 0.5 s = u x t = 20 x 0.5 = 10 m

distance travel by the car after the break is pressed

Using equation of motion

v² = u² + 2 a s

0² = 20² - 2 x 10 x s

s = 20 m

Total distance travel by the car = 20 + 10 = 30 m

Distance between deer and car = 49-30 = 19 m.

b. Maximum speed a car could have

Distance travel by the car in reaction time = v' x 0.5

v' is the maximum speed of the car.

maximum distance car can cover = 49 - 0.5 v'

Now, Using equation of motion

v² = u² + 2 a s

0² =v'² - 2 x 10 x (49- 0.5 x v')

v'² +10 v' -980 = 0

By solving

v = 26.7 m/s

Hence, maximum speed of the car can be 26.7 m/s

4 0

4 years ago

Jorge rides his bicycle to school every morning. The school is 4 km away from Jorge's house and it takes him 30 minutes to ride

Liono4ka [1.6K]

D. Speed
"Jorge's Average SPEED is 8km/hr"
hope I helped! also when doing multiple choice try using process of elimination. helps alot :P

5 0

3 years ago

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is +8.0 nC (+8.0 10-9 C), how ma

Ann [662]

Answer:

Number of electron on the fur will be $5\times 10^{10}electron$

Explanation:

We have given net charge on the fur $q=8nC=8\times 10^{-9}C$

Charge on one electron $e=1.6\times 10^{-19}C$

Let there are n number of electrons

So $ne=8\times 10^{-9}$

$n\times 1.6\times 10^{-19}=8\times 10^{-9}$

$n=5\times 10^{10}electron$

So number of electron on the fur will be $5\times 10^{10}electron$

6 0

3 years ago