A baseball player at practice is pushing a tackling dummy across the field. He initially has to push the 130 kg dummy with 600 N
1 answer:
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Answer:
The weight of any object will depend on its location in the universe, commanded by the law of gravitacion universal de Newton
Explanation:
Everything obeys the law of universal gravity proposed by Newton. Where the attraction force with which one body attracts another depends on the mass of the body that attracts the body with less mass, the radius of the body with the greatest mass and the universal gravitational constant.
For a better understanding of this concept let us use examples with numeric values. In the first example we will determine with what force planet Earth attracts a person of 70 [kg].
And in the second example we will perform the same exercise but on a planet like Jupiter
Example 1:
A person with a mass of 70 [kg] is located on planet Earth which has a mass of 5.97x10^24 [kg] and a terrestrial radius of 6371 [km]. Find the force exerted by the planet upon the person.
We have the law of universal gravity
Now replacing the values in the equation we have:
We can appreciate that if we only use the terms of mass of the earth, the gravitational constant and the radius of the earth, we will have the value of the gravity accelaration of the earth. Let's check
Example 2:
A person with a mass of 70 [kg] is located on planet Jupiter which has a mass of 1.899x10^27 [kg] and a radius of 71492 [km]. Find the force exerted by the planet upon the person.
We will calculate the value of the gravity accelaration of Jupiter. Let's check
Therefore an object in jupiter will weigh more than 2.5 times its weight than on planet Earth.
We found that the force of attraction or the weight of any object will depend on its location in the universe, commanded by the law of gravitacion universal de Newton
Answer:
The answer to your question is 5.5 x 10¹² kg/km³
Explanation:
Data
density = rho = X
mass = 5.94 x 10²⁴ kg
volume = 1.08 x 10¹² km³
Process
To solve this problem use the density formula and simplify it to find the result.
Formula
density =
Substitution
density =
Simplification and result
density = 5.5 x 10¹² kg/km³
Answer:108.71 mL
Explanation:
Given
Volume of sample V=150 mL
concentration of sucrose solution 35 % w/w i.e. In 100 gm of sample 35 gm is sucrose
specific gravity =1.115
Density of solution
Thus
mass of sample
mass of sucrose
mass of Water
Volume of water