Explanation:
The given data is as follows.
Spring constant (k) = 78 N/m, 
Mass of block (m) = 0.50 kg
According to the formula of energy conservation,
mgh sin
h =
= 
= 0.64 m
Thus, we can conclude that the distance traveled by the block is 0.64 m.
Answer:
108.37°C
Explanation:
P₁ = Initial pressure = 101 kPa
V₁ = Initial volume = 530 m³
T₁ = Initial temperature = 10°C = 10+273.15 =283.15 K
P₂ = Final pressure = 101 kPa (because it is open to atmosphere)
V₂ = Final volume = 530 m³
P₁V₁ = n₁RT₁
⇒101×530 = n₁RT₁
⇒53530 J = n₁RT₁
P₂V₂ = n₂RT₂
⇒53530 J = n₂RT₂

Dividing the first two equations we get

∴Temperature must the air in the balloon be warmed before the balloon will lift off is 381.25-273.15 = 108.37°C
Answer:
Explanation:
radius of hoop and the radius of disk is same = R
Let the mass of hoop is M and the mass of disk is M'.
As they reach the bottom of teh surface in same time so they travel equal distance thus, they have same acceleration.
The acceleration is given by

As the acceleration is same so that the moment of inertia is also same.
Moment of inertia of disk = moment of inertia of hoop
1/2 x mass of disk x R² = mass of hoop x R²
So, mass of disk = 2 x mass of hoop
Option (c) is correct.
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