Explanation:
When an object moves in a circular path, it will have circular acceleration. Its magnitude of acceleration is given by :
Since, 
T is the time period
R is the radius of the circular path
To increase the centripetal acceleration bu a factor of 1.5 or 3/2, radius of circle must be increase by a factor of 6 and T is increased by a factor of 2 such that,
R'=6R and T'=2T
So,
Hence, this is the required solution.
1. The Egg Drop.
2. The Car down a ramp.
3. Maybe an Airplane race with things on it.
I think it’s B, conduction.
Answer:
a) frictional force = 93.8 N
b) acceleration = 1.29 ms∧-2
Explanation:
The frictional force can be calculated by :
μ k = Fk / N
where:
- μ k = coefficient of kinetic friction = 0.14
- N= normal force or the force perpendicular to the contacting surface
- Weight of the crate, W = mg = (67 × 10) == 670 N
take acceleration due to gravity = 10m/s∧2
The normal force , N = W = 670N ( upward force equals downward force)
Fk = μ k × N
= 0.14 × 670
Fk = 93.8 N
b) To calculate the magnitude of crate's acceleration
F - Fk = ma
where
- Fk = frictional force = 93.8N
- F = horizontal force = 180 N
- m = mass = 67.0 kg
- a = magnitude of acceleration (unknown)
by substituting,
180 - 93.8 = 67a
86.2 = 67a
acceleration, a = (86.2 ÷ 67)
a = 1.29 ms∧-2
According to the periodic table, all the elements, except hydrogen, are considered alkaline metals. ie. Li, Na, K, Rb, Cs, Fr.
