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Setler79 [48]
3 years ago
7

A concave lens can only form a. A. real image. B. reversed image. C. virtual image. D. magnified image.

Physics
1 answer:
skad [1K]3 years ago
4 0
A concave lens can only form a:

<span>C. virtual image. </span>
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Answer:a and c

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Why are magnetic fields evidence of sea floor spreading
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Fine grains of beach sand are assumed to be spheres of radius 64.8 µm. These grains are made of silicon dioxide which has a dens
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Answer:

1) Mass of the grain is 2.9632\times 10^{-9} kg.

2) 0.08901 kg of sand would have surface area equal the surface area of the cube.

Explanation:

1) Radius of the grain,r = 64.8 µm =6.48\times 10^{-5}m

Volume of the sphere =\frac{4}{3}\pi r^3

Volume of the grain of a sand:

V=\frac{4}{3}\times \pi r^3=\frac{4}{3}\times 3.14\times (6.48\times 10^{-5} m)^3

V=1.1397\times 10^{-12} m^3

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Mass of a grain of a sand = M

d=2600 kg/m^3=\frac{M}{1.1397\times 10^{-12} m^3}

M=2.9632\times 10^{-9} kg

Mass of the grain is 2.9632\times 10^{-9} kg.

2) Surface are of sphere: 4\pi r^2

Surface area of a grain:

A=4\times 3.14\times (6.48\times 10^{-5}m)^2

A=5.2766\times 10^{-8} m^2

Length of the cube = a = 0.514 m

Total surface area of cube ,A'= 6a^2

A'=6\times (0.514 m)^2=1.5851 m^2

let the number grains with area equal to total surface area of cube be x.

A'=A\times x

x=\frac{1.5851 m^2}{5.2766\times 10^{-8} m^2}=3.003\times 10^7

Volume of x number of grains :V'

V'=V\times x

V= 1.1397\times 10^{-12} m^3\times 3.003\times 10^7

V'=3.4236\times 10^{-5} m^3

Mass of 3.4236\times 10^{-5} m^3 of sandL:

=3.4236\times 10^{-5} m^3\times 2600 kg/m^3=0.08901 kg

0.08901 kg of sand would have surface area equal the surface area of the cube.

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