A) About 9.1 B) about 14.1 C) about 17.2 D) about 18.1 Please help me
1 answer:
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Answer:
The appropriate answer is "72.8 m".
Explanation:
Let the distance be "x".
As per the question, we get
⇒
or,
⇒
By taking L.C.M, we get
⇒
By applying cross-multiplication, we get
⇒
⇒
⇒
The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>- As we know that the expression of pressure as,
where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
- It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,
- From this, the value of weight will be,
Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
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