1. Col2
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Answer:
36.08%
Explanation:
We are given the overall formula of the compound as: CuSO4•5H2O
Now, atomic mass of the elements are;
Cu = 63.55 g/mol
S = 32.07 g/mol
O = 16 g/mol
H20 = 18.02 g/mol
Now, let's calculate the total mass of the compound:
(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol
From the above, water in the compound is 5(H20)
Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol
Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%
Percentage of water = (90.1/249.72) × 100% = 36.08%
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Answer:
Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)
Explanation:
Let's consider the following molecular equation.
Mg(s) + SnSO₄(aq) ⇄ MgSO₄(aq) + Sn(s)
The full ionic equation includes al the ions and the species that do not dissociate in water.
Mg(s) + Sn²⁺(aq) + SO₄²⁻(aq) ⇄ Mg²⁺(aq) + SO₄²⁻(aq) + Sn(s)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the species that do not dissociate in water.
Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)
The rate of the reaction is measurable quantity that refers to the amount or how much is are chemical substances reagents used up or converted into the product over some period of time.
Rate = change in the amount/time.
This can indirectly be observed through many ways, such as the volume of gas given off if the byproduct is a gas being produced, the colour of the solution etc.
