C. ability to bond is a chemical property of tin.
The concentration of
in the stack gas = 12 ppmv
That means 12 L of
is present per ![10^{6} L gas](https://tex.z-dn.net/?f=%2010%5E%7B6%7D%20L%20gas%20)
The given temperature is 273 K (0 C) and pressure is 1 atm. At these conditions, 1 mol of gas would occupy,
![PV = nRT](https://tex.z-dn.net/?f=%20PV%20%3D%20nRT%20)
![(1 atm) (V) = (1 mol)(0.08206\frac{L.atm}{mol.K}) (273 K)](https://tex.z-dn.net/?f=%20%281%20atm%29%20%28V%29%20%3D%20%281%20mol%29%280.08206%5Cfrac%7BL.atm%7D%7Bmol.K%7D%29%20%28273%20K%29%20)
V = 22.4 L
1 mol
occupies 22.4 L
Moles of
= ![12 L *\frac{1 mol}{22.4 L} = 0.5357 mol SO_{2}](https://tex.z-dn.net/?f=%2012%20L%20%2A%5Cfrac%7B1%20mol%7D%7B22.4%20L%7D%20%3D%200.5357%20mol%20SO_%7B2%7D%20%20%20%20)
Mass of
=
=
μg
Converting
:
= ![10^{3} m^{3}](https://tex.z-dn.net/?f=%2010%5E%7B3%7D%20%20%20m%5E%7B3%7D%20%20%20)
Calculating the concentration in μg/
:
![\frac{3.432 * 10^{7} microgram}{10^{3} L} = 3.432 * 10^{4} microgram/m^{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3.432%20%2A%2010%5E%7B7%7D%20microgram%7D%7B10%5E%7B3%7D%20L%7D%20%20%20%20%3D%203.432%20%2A%2010%5E%7B4%7D%20%20microgram%2Fm%5E%7B3%7D%20%20)
A chemical reaction is going to be your answer
Since orbital period depends on how far you are from the sun, planets closer to the sun have a orbital period less than one earth year.
These planets are Mercury and Venus
Answer:
80% left thanks hope ur day will fine