You didn't provide answer choices so I will answer this to the best of my ability and hope it helps.....
1. corporal
2. earthy
3. material
4. manuel
I hope these answers can help you.
Answer:
3.39724 seconds
23.0824792352 m, 101.917520765 m
13.58896 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
The equation of motion will be


The time at which the cars collide is 3.39724 seconds

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

The speed of car B is 13.58896 m/s
To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.
By definition the torque is defined as

Where,

F = Force
r = Radius
For our values we have:



Consequently the calculation of the moment of inertia would then be given by the relationship


Replacing with our values


The moment of inertia of the boxer's forearm 
Answer:
A) 32.22 N/m b) 0.0156 m c) 4 Hz
Explanation:
Using Hooke's law;
T = 2π √m/k where m is mass of the body in kg and k is the force constant of the spring N/m and T is the period of vibration in s.
M = 51 g = 51 / 1000 in kg = 0.051kg
Make k subject of the formula
T/2π = √m / k
Square both sides
T^2 / 4π^2 = m/k
Cross multiply
K = 4 π^2 * m/T^2
K = 4 * 3.142 * 3.142 * 0.051/ 0.25^2= 32.22N/m
B) using Hooke's law;
F = k e where e is the maximum displacement of the spring from equilibrium point called amplitude
F= weight of the body = mass * acceleration due to gravity = 0.051*9.81
0.5 = 32.22 * e
e = 0.5/32.22 = 0.0156 m
C) frequency is the number of cycle completed in a second = 1 / period
F = 1 / 0.25 = 4Hz