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Marta_Voda [28]
3 years ago
7

A 62-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 821 N. What is the acceleration

of the elevator?
Physics
2 answers:
Karolina [17]3 years ago
7 0
<h2>Answer:</h2>

3.24m/s^{2}

<h2>Explanation:</h2><h2></h2>

Using Newton's law of motion,

F = ma   ..........................(i)

where;

F = net force acting on the object (or body)

m = mass of the object (or body)

a = acceleration of the body.

<em>In this case,</em>

Two forces are acting;

(i)The weight (W) of the man  = m x g = 62 x 10 = 620N

(ii)The tension (T) on the scale of the elevator = 821N

The weight(W) of the man is a downward force while the tension (T) on the scale of the elevator is an upward force. Since the elevator rises upward is positive.

Therefore,

Net force (F) = Total upward force(s) - Total downward force(s)

Net force (F) = 821 - 620

F = 201N

To calculate the acceleration of the elevator,

substitute the values of F = 201N and m = 62 into equation (i) above;

=> F = ma

=> 201 = 62 x a

=> a = 210 / 62

=> a = 3.24m/s^{2}

Therefore the acceleration of the elevator is 3.24m/s^{2}

FromTheMoon [43]3 years ago
5 0

Answer:

Acceleration of the elevator = 13.242 m/s2.

Explanation:

Force is defined as the push or pull on an object with mass in kg that causes a change velocity. Force as a vector means it has both magnitude and direction.

Mathematically,

F = M*a

Where

F = force in Newton.

M = mass of the object in kg.

a = acceleration due to gravity in 9.81 m/s2.

Acceleration of the elevator = 821/62

= 13.242 m/s2.

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An oscillator consists of a block attached to a spring (k = 500 N/m). At some time t, the position (measured from the system's e
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a) \omega = 10.407\,\frac{rad}{s}, b) m = 4.617\,kg, c) A = 1.355\,m

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a) The system have a simple armonic motion, whose position function is:

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The velocity function is determined by deriving the position function in terms of time:

v(t) = -\omega \cdot A \cdot \sin(\omega\cdot t + \phi)

The acceleration function is found by deriving again:

a(t) = -\omega^{2} \cdot A \cdot \cos (\omega\cdot t + \phi)

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A\cdot \cos \phi = 0.660\,m

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-\omega^{2}\cdot A \cdot \sin \phi = -128\,\frac{m}{s^{2}}

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\omega \cdot \tan \phi = 18.636\,\frac{1}{s}

\omega^{2}\cdot \tan \phi = 193.94\,\frac{1}{s^{2}}

Now, the last expression is divided by the first one:

\omega = 10.407\,\frac{rad}{s}

b) The mass of the block is:

m = \frac{k}{\omega^{2}}

m = \frac{500\,\frac{N}{m} }{(10.407\,\frac{rad}{s})^{2} }

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\phi = \tan^{-1} \left(\frac{18.636\,\frac{1}{s} }{\omega}  \right)

\phi \approx 0.338\pi

The amplitude is:

A = \frac{0.660\,m}{\cos 0.338\pi}

A = 1.355\,m

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