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Marta_Voda [28]
3 years ago
7

A 62-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 821 N. What is the acceleration

of the elevator?
Physics
2 answers:
Karolina [17]3 years ago
7 0
<h2>Answer:</h2>

3.24m/s^{2}

<h2>Explanation:</h2><h2></h2>

Using Newton's law of motion,

F = ma   ..........................(i)

where;

F = net force acting on the object (or body)

m = mass of the object (or body)

a = acceleration of the body.

<em>In this case,</em>

Two forces are acting;

(i)The weight (W) of the man  = m x g = 62 x 10 = 620N

(ii)The tension (T) on the scale of the elevator = 821N

The weight(W) of the man is a downward force while the tension (T) on the scale of the elevator is an upward force. Since the elevator rises upward is positive.

Therefore,

Net force (F) = Total upward force(s) - Total downward force(s)

Net force (F) = 821 - 620

F = 201N

To calculate the acceleration of the elevator,

substitute the values of F = 201N and m = 62 into equation (i) above;

=> F = ma

=> 201 = 62 x a

=> a = 210 / 62

=> a = 3.24m/s^{2}

Therefore the acceleration of the elevator is 3.24m/s^{2}

FromTheMoon [43]3 years ago
5 0

Answer:

Acceleration of the elevator = 13.242 m/s2.

Explanation:

Force is defined as the push or pull on an object with mass in kg that causes a change velocity. Force as a vector means it has both magnitude and direction.

Mathematically,

F = M*a

Where

F = force in Newton.

M = mass of the object in kg.

a = acceleration due to gravity in 9.81 m/s2.

Acceleration of the elevator = 821/62

= 13.242 m/s2.

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Free_Kalibri [48]

Explanation:

It is given that,

Mass of object, m = 2 kg

Initial velocity, u = 3 m/s (east)

Final velocity, v = - 7 m/s (west)

The Impulse can be calculated using the change in momentum of an object i.e.

J = m(v-u)

J=2\ kg(-7\ m/s-3\ m/s)

J = -20 kg-m/s

So, the Impulse of this object is 20 kg-m/s but the direction is opposite. Hence, statement (1) is correct i.e. Student #1: "The impulse is equal to the change in momentum, which is (2 kg)(3 m/s + 7 m/s) = 20 kg m/s."

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2 years ago
A space craft is traveling in interplanetary space at a constant velocity. what is the estimated distance traveled by the space
mina [271]

Answer:

A. 2.30 x 10^2 kil

Explanation:

3/2 = 1.5 and 0.72/2 = 0.36

1.93 + 0.36 = 2.29

2.29 = about 2.30

7 0
2 years ago
Part A Which of the following statements is/are true? Check all that apply.
viva [34]

Answer:

A) True

C)True

D)True

Explanation:

As we know that power is the rate at which work is done.

We know that mechanical work w given as

 w = ∫F.ds

F=Force

ds = Elemental displacement

So power P = F.V

V=Velocity

F=Force

The unit of power in SI unit is Watt or joule per second (J/s).But on the other hand the unit of power in English system is horsepower.

The is also can be defined as the rate at which energy is transformed.

Following option are corrects

A) True

C)True

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4 0
2 years ago
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The way a concave mirror works is that since it's concave, the light bounces off of each other. a convex mirror, it curved the opposite, and the mirror has no way to bounce off of itself.

6 0
1 year ago
Learning Goal:
enot [183]

Answer:

A. U_0 = \dfrac{\epsilon_0 A V^2}{2d}

B. U_1 = \dfrac{\epsilon_0 A V^2}{6d}

C. U_2 = \dfrac{K\epsilon_0 A V^2}{2d}

Explanation:

The capacitance of a capacitor is its ability to store charges. For parallel-plate capacitors, this ability depends the material between the plates, the common plate area and the plate separation. The relationship is

C=\dfrac{\epsilon A}{d}

C is the capacitance, A is the common plate area, d is the plate separation and \epsilon is the permittivity of the material between the plates.

For air or free space, \epsilon is \epsilon_0 called the permittivity of free space. In general, \epsilon=\epsilon_r \epsilon_0 where \epsilon_r is the relative permittivity or dielectric constant of the material between the plates. It is a factor that determines the strength of the material compared to air. In fact, for air or vacuum, \epsilon_r=1.

The energy stored in a capacitor is the average of the product of its charge and voltage.

U = \dfrac{QV}{2}

Its charge, Q, is related to its capacitance by Q=CV (this is the electrical definition of capacitance, a ratio of the charge to its voltage; the previous formula is the geometric definition). Substituting this in the formula for U,

U = \dfrac{CV^2}{2}

A. Substituting for C in U,

U_0 = \dfrac{\epsilon_0 A V^2}{2d}

B. When the distance is 3d,

U_1 = \dfrac{\epsilon_0 A V^2}{2\times3d}

U_1 = \dfrac{\epsilon_0 A V^2}{6d}

C. When the distance is restored but with a dielectric material of dielectric constant, K, inserted, we have

U_2 = \dfrac{K\epsilon_0 A V^2}{2d}

6 0
2 years ago
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