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Eva8 [605]
3 years ago
14

What is the end result when the sulfur dioxide and nitrogen oxide produced by burning fossil fuels react with the atmospheric mo

isture?
Chemistry
2 answers:
Ivan3 years ago
8 0
Global warming can take place from the fuel/moisture ratio.
Firdavs [7]3 years ago
8 0
<span>When sulfur dioxide and nitro oxide emissions react with water vapor in the atmosphere, it form acids that return to the surface, either as a dry or wet deposition, or more commonly known as acid rain.

</span>Acid deposition <span>is a general name for a number of phenomena, namely </span>acid<span> rain, </span>acid<span> fog and </span>acid<span> mist. This means it can imply both wet and dry (gaseous) precipitation.</span>
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Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).
SIZIF [17.4K]
5.20 mol C6H12* (84.2 g/mol C6H12)= 4.38*10^(2) g C6H12.

The answer should only have three significant figures, according to the numbers in the problem.

Hope this is helpful~
7 0
3 years ago
Hydrogen chloride gas and oxygen gas react to form water and chlorine gas. A reaction mixture initially contains 53.2 g of hydro
Sergio [31]

<u>Answer:</u> The mass of the excess reactant (oxygen gas) is 3.136 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For HCl:</u>

Given mass of HCl = 53.2 g

Molar mass of HCl = 36.5 g/mol

Putting values in equation 1, we get:

\text{Moles of HCl}=\frac{53.2g}{36.5g/mol}=1.46mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 26.5 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{26.5g}{32g/mol}=0.828mol

The chemical equation for the reaction of HCl and oxygen gas follows:

2HCl+O_2\rightarrow H_2O+Cl_2

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of oxygen gas

So, 1.46 moles of HCl will react with = \frac{1}{2}\times 1.46=0.73mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, HCl is considered as a limiting reagent because it limits the formation of product.

Excess moles of oxygen gas = (0.828 - 0.73) = 0.098 moles

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Excess moles of oxygen gas = 0.098 moles

Putting values in equation 1, we get:

0.098mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.098mol\times 32g/mol)=3.136g

Hence, the mass of the excess reactant (oxygen gas) is 3.136 grams

4 0
3 years ago
Help me out here please???
san4es73 [151]

Answer:

A

Explanation:

5 0
3 years ago
Read 2 more answers
Calcium Carbonate decomposes at 1200°C to form carbon dioxide and
Travka [436]

This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally.

To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for V2, which we can obtain by rearranging the equation into V2 = V1T2/T1. Given V1 = 25 L, T1 = 1200 °C (1473.15 K), and T2 = 25 °C (298.15 K):

V2 = (25 L)(298.15 K)/(1473.15 K) = 5.1 L.  

5 0
4 years ago
1. When a metal and a(n) ___ bond, they do not share electrons. 2. The ___ atom transfers one or more valence electrons to the _
NISA [10]

Answer:

1 . Nonmetal

2. metal, non metal

3. Ion

4. positive

5 0
4 years ago
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