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Delicious77 [7]
4 years ago
15

What is a bond between a positive and negative ion called?

Chemistry
2 answers:
BartSMP [9]4 years ago
7 0
B) ionic bond

(although in reality, every bond is fundamentally the sharing of a pair of electron. but due to unmutal electonegativity, the molecule becomes polar)
djverab [1.8K]4 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

An ionic bond is defined as the bond formed due to transfer of electron(s) from one atom to another.  

An ionic bond will always be formed between a metal and a non-metal.

For example, sodium metal on donating its one valence electron to chlorine atom will lead to the formation of NaCl compound.

This is because an atom which loses its valence electrons (metals) acquires a positive charge and another atom which gains the electrons (non-metals) acquires a negative charge.  

Hence, these opposite charges strongly gets attracted towards each other forming a strong bond.

Whereas in a covalent bond, there will be sharing of electrons between the combining atoms.

For example, an O_{2} molecule is formed due to sharing of electrons between the two oxygen atoms.

Thus, we can conclude that a bond between a positive and negative ion called an ionic bond.

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In July 1994 the comet shoemaker-levy 9 collided with the planet Jupiter, as scientists had predicted. To be able to accurately
Korvikt [17]

Answer:

the gravitational attraction that exists between all bodies

Explanation:

Comet shoemaker-levy 9 was the comet that broke away and collided with the largest planet on our solar system, the Jupiter. The comet fall apart from the asteroids in the year 1992 and flew and hit Jupiter in the year 1994. This was predicted by the scientist.

Similarly when a comet can hit a planet can be accurately predicted by the scientist or the researcher by understanding and studying the gravitational forces that exists between the bodies in the solar system. It is very important to understand the gravitational attractions which exists between all the bodies in the universe in order to calculate or predict when can a comet collide with a planet.

5 0
3 years ago
What is the boiling point of cyclohexane at 620 mmhg? can you show calculations?
Anton [14]

 Boiling point of cyclohexane at 620 mm hg?  

Standard atmospheric pressure is 760 mm Hg. Boiling point at 760 mm= 80.74˚C  

A liquid boils when its vapor pressure is equal to the atmospheric pressure. The vapor pressure of a liquid is proportional the absolute temperature of the liquid.  

As the atmospheric pressure decreases, less vapor pressure is needed to cause the liquid to boil. Less vapor pressure means lower temperature.  

The boiling point of cyclohexane at 620 mm Hg is less than 80.74˚C



TRY THAT OR THIS

 

271.78

7 0
3 years ago
Read 2 more answers
The first step in deforestation in the Amazon is _______. A. Logging b. Farming c. Ranching d. Road building.
scoray [572]

Answer:

Explanation: The answer is A. logging

3 0
3 years ago
Calculate ΔH o rxn for the following: CH4(g) + Cl2(g) → CCl4(l) + HCl(g)[unbalanced] ΔH o f [CH4(g)] = −74.87 kJ/mol ΔH o f [CCl
anzhelika [568]

Answer:  ΔH for the reaction is -277.4 kJ

Explanation:

The balanced chemical reaction is,

CH_4(g)+Cl_2(g)\rightarrow CCl_4(l)+HCl(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H(products)]-\sum [n\times \Delta H(reactant)]

\Delta H=[(n_{CCl_4}\times \Delta H_{CCl_4})+(n_{HCl}\times B.E_{HCl}) ]-[(n_{CH_4}\times \Delta H_{CH_4})+n_{Cl_2}\times \Delta H_{Cl_2}]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta H=[(1\times -139)+(1\times -92.31) ]-[(1\times -74.87)+(1\times 121.0]

\Delta H=-277.4kJ

Therefore, the enthalpy change for this reaction is, -277.4 kJ

4 0
3 years ago
Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -> 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0
3 years ago
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