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Delicious77 [7]
4 years ago
15

What is a bond between a positive and negative ion called?

Chemistry
2 answers:
BartSMP [9]4 years ago
7 0
B) ionic bond

(although in reality, every bond is fundamentally the sharing of a pair of electron. but due to unmutal electonegativity, the molecule becomes polar)
djverab [1.8K]4 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

An ionic bond is defined as the bond formed due to transfer of electron(s) from one atom to another.  

An ionic bond will always be formed between a metal and a non-metal.

For example, sodium metal on donating its one valence electron to chlorine atom will lead to the formation of NaCl compound.

This is because an atom which loses its valence electrons (metals) acquires a positive charge and another atom which gains the electrons (non-metals) acquires a negative charge.  

Hence, these opposite charges strongly gets attracted towards each other forming a strong bond.

Whereas in a covalent bond, there will be sharing of electrons between the combining atoms.

For example, an O_{2} molecule is formed due to sharing of electrons between the two oxygen atoms.

Thus, we can conclude that a bond between a positive and negative ion called an ionic bond.

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A gas system has an initial number of moles of 0.693 moles with the volume unknown. When the number of moles changes to 0.928 mo
lara [203]

Answer:

The initial volume in mL is 5959.2 mL

Explanation:

As the number of moles of a gas increases, the volume also increases.  Hence, number of moles and volumes are directly proportional i.e

n ∝ V

Where n is the number of moles and V is the volume

Then, n = cV

c is the proportionality constant

∴n/V = c

Hence n₁/V₁ = n₂/V₂

Where n₁ is the initial number of moles

V₁ is the initial volume

n₂ is the final number of moles

and V₂ is the final volume.

From the question,

n₁ = 0.693 moles

V₁ = ?

n₂ = 0.928 moles

V₂ = 7.98 L

Putting the values into the equation

n₁/V₁ = n₂/V₂

0.693 / V₁ = 0.928 / 7.98

Cross multiply

∴ 0.928V₁ = 0.693 × 7.98  

0.928V₁ = 5.53014

V₁ = 5.53014/0.928

V₁ = 5.9592 L

To convert to mL, multiply by 1000

∴ V₁ = 5.9592 × 1000 mL

V₁ = 5959.2 mL

Hence, the initial volume in mL is 5959.2 mL

5 0
3 years ago
What volume of oxygen is needed to react with 20cm3 of ethane?
Anna71 [15]

Answer:

The reaction states that 2 moles of ethane react with 7 moles of oxygen. At standard temperature and pressure conditions (STP), each mole of gas occupies a volume of 22.4 liters. Therefore, 2 moles of ethane occupy liters, and 7 moles of oxygen occupy liters. In other words: 6 liters.

Explanation:

I hope it helps you

7 0
3 years ago
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