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OLEGan [10]
3 years ago
12

A 0.5 kg ball was kicked and was going 15 m/s.What is the kinetic energy of the ball?

Physics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 56.25 \ Joules}}

Explanation:

Kinetic energy can be found using the following formula:

E_k=\frac{1}{2}mv^2

where <em>m </em>is the mass and <em>v</em> is the velocity.

The mass of the ball is 0.5 kilograms and the velocity is 15 meters per second

m= 0.5 \ kg \\v= 15 \ m/s \\

Substitute the values into the formula.

E_k=\frac{1}{2} (0.5 \ kg ) * (15  \ m/s)^2

First, evaluate the exponent.

  • (15 m/s)²= (15 m/s) * (15 m/s) = 225 m²/s²

E_k=\frac{1}{2} (0.5 \ kg ) *(225 \ m^2/s^2)

Multiply 0.5 kg by  225 m²/s²

E_k=\frac{1}{2}(112.5 \ kg* m^2/s^2)

Multiply 112 kg*m²/s² by 1/2, or divide by 2.

E_k=56.25 \ kg*m^2/s^2

  • 1 kg*m²/s² is equal to 1 Joule
  • Therefore, our answer of 56.25 kg*m²/s² is equal to 56.25 Joules.

E_k= 56.25 \ J

The kinetic energy of the ball is <u>56.25 Joules</u>

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