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Ilya [14]
3 years ago
13

Which best describes proper disposal technique? A bin should be labeled “chemical wastes and hazardous waste.” A bin should be l

abeled “chemical wastes and broken glass.” Students should know proper disposal of the chemicals they use. Students can dispose of all chemicals in the sink.
Physics
2 answers:
Sergeeva-Olga [200]3 years ago
5 0
Chemical wastes and broken glasses
DanielleElmas [232]3 years ago
3 0

Answer: ''A bin should be labeled “chemical wastes and broken glass.”

Explanation:

The waste disposal is issue is the primary concern for the laboratory staff or others who daily work in labs. It should be done with utmost precaution and care.

Among the options given, ''A bin should be labeled “chemical wastes and broken glass.” is the correct option. This is because of the fact that chemical wastes can be hazardous. They can catch fire with air or may cause burns and injury if they accidentally come in contact with the skin. The broken glass may exhibit sharp edges which can be injurious. Therefore, the bin which contains either chemical wastes or broken glass must be labelled properly so as prevent hazards and injuries in the laboratory.

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A particle of unit mass moves in a potential V(x)= ax^2+b/x^2 . Where a and b are constnts. Calcuate the angular frequency of sm
Sholpan [36]

Answer:

Explanation:

Given

Potential Energy is given by

U(x)=ax^2+\frac{b}{x^2}

And Force is given by

F=-\frac{\mathrm{d} U}{\mathrm{d} x}

Particle will be at equilibrium when Potential Energy is either minimum or maximum

F=-\left ( 2ax-\frac{2b}{x^3}\right )

i.e.ax=\frac{b}{x^3}

x_0=(\frac{b}{a})^{0.25}

So angular Frequency of small oscillation is given by

\omega =\sqrt{\frac{U''(x)}{m}}

for m=1

we get    \omega =\sqrt{\frac{U''(x_0)}{1}}

U''(x_0)=2a+6a= 8a

\omega =\sqrt{8a}

4 0
3 years ago
Sr-38<br><br> K-19<br><br> K-59<br><br> K-40
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Answer:

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Explanation:

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6 0
3 years ago
A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2
hammer [34]

Answer:

2m/s²

Explanation:

Given parameters:

Net force on the car  = 2000N

Acceleration = 4m/s²

Unknown:

Acceleration of a car twice the mass  = ?

Solution:

Let us first find the mass of the car;

 Force  = mass x acceleration

         Mass = \frac{Force }{acceleration}  

 Mass = \frac{2000}{4}   = 500kg

 Now,

     whose mass is twice that of the car

    Mass of the new car = 2 x 500  = 1000kg

So;

  Acceleration  = \frac{Net force }{mass}  

  Acceleration  = \frac{2000}{1000}  = 2m/s²

3 0
3 years ago
Which statement about covalent bonds is true
g100num [7]
In covalent bonds the atoms share electrons.
7 0
3 years ago
Read 2 more answers
A block of weight mg sits on an inclined plane as shown in (Figure 1) . A force of magnitude F1 is applied to pull the block up
svlad2 [7]

Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

Y Axis  

       N - W_{y} =

       N = W_{y}

X axis

       F1 - fr - Wₓ = 0

       fr = F1 - Wₓ

Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     cos θ = W_{y} / W

      Wₓ = W sin θ

      W_{y} = W cos θ

We substitute

      fr = F1 - W sin θ

Work is defined by

        W = F .dx

        W = F dx cos θ

The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

4 0
3 years ago
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