1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ilya [14]
3 years ago
13

Which best describes proper disposal technique? A bin should be labeled “chemical wastes and hazardous waste.” A bin should be l

abeled “chemical wastes and broken glass.” Students should know proper disposal of the chemicals they use. Students can dispose of all chemicals in the sink.
Physics
2 answers:
Sergeeva-Olga [200]3 years ago
5 0
Chemical wastes and broken glasses
DanielleElmas [232]3 years ago
3 0

Answer: ''A bin should be labeled “chemical wastes and broken glass.”

Explanation:

The waste disposal is issue is the primary concern for the laboratory staff or others who daily work in labs. It should be done with utmost precaution and care.

Among the options given, ''A bin should be labeled “chemical wastes and broken glass.” is the correct option. This is because of the fact that chemical wastes can be hazardous. They can catch fire with air or may cause burns and injury if they accidentally come in contact with the skin. The broken glass may exhibit sharp edges which can be injurious. Therefore, the bin which contains either chemical wastes or broken glass must be labelled properly so as prevent hazards and injuries in the laboratory.

You might be interested in
The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P
bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

a=\dfrac{P}{m}

a=\dfrac{181\ N}{68\ kg}

a=2.67\ m/s^2

(c) P = 352 N

a=\dfrac{P}{m}

a=\dfrac{352\ N}{68\ kg}

a=5.17\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
a roller coaster is at the top of a hill and rolls to the top of a lower hill.If mechanical energy is conserved,on the top of wh
pychu [463]
Hello!!

Here we have a simple matter of conservation of energy. ME=PE+KE.

At point A we have PE=mgh and KE=1/2mv^2. At point A all we have is PE since the coaster isn’t rolling yet. But by conservation of energy, we know that it will have enough energy to roll down and get to and equal height on another hill. Providing we are neglecting friction and drag and resistance forces which we are in this case. So we can conclude that the KE will be greater at Point B since ME=PE+KE and for ME to remain the same and we know the PE is less on lower hill, so we can conclude that KE on lower hill is greater to keep ME the same and have conservation of energy.

Hope this helps you understand the concept!! Any questions please just ask!! Thank you so much!!
7 0
3 years ago
. Một con lắc đơn có chiều dài dây treo 1m dao động điều hoà treo trong một xe chạy trên mặt phẳng nghiêng
lyudmila [28]

Answer:

C

Explanation:

hope for help ....im expert

6 0
3 years ago
Read 2 more answers
a football player kicks a ball with a mass of 0.42kg. The average acceleration of the football was 14.8 m/s2. How much force did
Zarrin [17]

Answer:

6.216 N

Explanation:

As for Newton's second law of motion

F=ma

where F= the acting force

           m=subjected mass

           a= the acceleration

applying F=ma to the football

F=m*a

 =0.42*14.8

 =6.216 N

6.216 N of a force is supplied to the ball

5 0
3 years ago
QUESTION 7
ryzh [129]

Answer:

<em>The force required is 3,104 N</em>

Explanation:

<u>Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+at

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

\displaystyle a=\frac{0-20.4}{7.4}

a=-2.757\ m/s^2

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

F = 1,126\ kg * 2.757\ m/s^2

F= 3,104 N

The force required is 3,104 N

6 0
3 years ago
Other questions:
  • A vertical spring with spring constant 23.15 N/m is hanging from a ceiling. A small object is attached to the lower end of the s
    11·1 answer
  • Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial accel
    10·1 answer
  • If the current in this circuit is 3 A, what must be the value of R3?
    15·1 answer
  • How many planets are there in the milky way galaxy?
    13·1 answer
  • The worked examples of charged-particle motion are relevant to:______. a. a transistor. b. a cathode-ray tube. c. magnetic reson
    11·1 answer
  • What is the difference between cytology and histology
    8·1 answer
  • Two small objects each with a net charge of Q (positive) exert a force of magnitude F on each other. We replace one of the objec
    9·1 answer
  • Name a radioactive gas that is released from the ground
    5·1 answer
  • An electric current of 0.75 A passes through a circuit that has a resistance of
    8·2 answers
  • What is international system of units?​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!