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Veronika [31]
3 years ago
8

. Answer the following: 7 x 2 = 141. Find 1. Find 2/3÷4​

Chemistry
2 answers:
Artist 52 [7]3 years ago
6 0

Explanation:

2/3 ÷ 4 = 0.166

I think this should be the answer

Afina-wow [57]3 years ago
5 0

Explanation:

\frac{2}{3}  \div 4

make \: 4 \: as \:  \frac{1}{4}  \: since \: is \: divide

\frac{2}{3}  \times  \frac{1}{4}

\frac{2}{12}  =  \frac{1}{6}

Hope this is correct and helpful

HAVE A GOOD DAY!

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What is one factor that contributes to seasons occurring in Pennsylvania?
Alenkinab [10]
The tilt of Earth on it's axis
6 0
3 years ago
A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
Ymorist [56]

Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

6 0
3 years ago
Need help !!!!! ASAP
Korolek [52]
<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

V_{2}=2.84L

<h2>Why?</h2>

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law,  and Boyle's Law.

The law is defined by the following equation:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}

Where,

P_{1} is the first pressure.

V_{1} is the first volume.

T_{1} is the first temperature.

P_{2} is the second pressure.

V_{2} is the second volume.

T_{2} is the second temperature.

So, we are given the following information:

V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K

Then, isolating the new volume, and substituting, we have:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L

Hence, the new volume is 2.84 L.

V_{2}=2.84L

Have a nice day!

4 0
4 years ago
The hardness of water (hardness count )is usually expressed in parts per million(by Mass) CaCO3, which is equivalent to milligra
Ksju [112]

Answer:

1.75 × 10⁻³ M

Explanation:

Given:

Hardness = 175 mg CaCO₃/L

or mass of CaCO₃ in 1 L = 175 × 10⁻³ grams

Now,

Molar mass of CaCO₃ = 40 + 12 + ( 3 × 12 ) = 100 grams/mol

The concentration of CaCO₃ = number of moles / volume

or

= (175 × 10⁻³ / 100) / 1

or

= 1.75 × 10⁻³ M

Now,

       CaCO₃         ⇒        Ca²⁺         +         CO₃²⁻

1.75 × 10⁻³ M          1.75 × 10⁻³ M         1.75 × 10⁻³ M

thus,

the concentration of Ca²⁺ ions in water = 1.75 × 10⁻³ M

4 0
3 years ago
How are molecules arranged inside solid, gas and liquids​
AlekseyPX

Answer:

Solid= all together in lines

Gas= floating round everywhere

Liquids = a lot more than gas but not all together like solid

8 0
3 years ago
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