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kompoz [17]
3 years ago
11

How many carbon atoms are present in a mole of 12C?

Chemistry
1 answer:
kondor19780726 [428]3 years ago
6 0
1 mol of carbon 12 would possess 6.02 X 10^23 carbon atoms.
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A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Us
drek231 [11]

Answer:6.0M

Explanation:see attached photo

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3 years ago
What is the mole, and why is it useful in chemistry?
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Answer:The mole is important because it allows chemists to work with the subatomic world with macro world units and amounts. Atoms, molecules and formula units are very small and very difficult to work with usually. However, the mole allows a chemist to work with amounts large enough to use.

Explanation:

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Sodium electron configuration in longhand notation
Elden [556K]

Answer:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Explanation:

Sodium is present in group 1.

It is alkali metal.

It has one valence electron.

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Its atomic mass is 23 amu.

The longhand notation of electronic configuration of sodium can be written as,

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

The electronic configuration in shorthand notation( noble gas) would be written as,

Na₁₁ = [Ne] 3s¹

Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.

It react with halogen and form salt. Such as sodium chloride.

2Na + Cl₂  →  2NaCl

5 0
3 years ago
In a machine shop, two cams are produced, one of aluminum and one of iron. Both cams have the same mass. Which cam is larger? (a
Lelu [443]
The best and most correct answer among the choices provided by your question is the second choice or letter B.

The iron cam is larger than the aluminum cam even if with the same size.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Read 2 more answers
Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^--------->Zn E°cell = -0.76 V Cu^2+ + 2 e^-----
Neko [114]

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

5 0
3 years ago
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