Answer:
0.1066 hours
Explanation:
A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.
t1/2 = ln2/k
t1/2 = ln2/6.5 h⁻¹
t1/2 = 0.1066 h
The half-life of the pesticide is 0.1066 hours.
Answer:
Thermal decomposition or cracking
Explanation:
Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.
Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.
When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.
Example is given below:
C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄
It expresses a cube using cm
Answer: Chyme
Explain: Chyme passes from the stomach to the small intestine. Further protein digestion takes place in the small intestine.
