f(x)=lnx
y=f(x)
dy/dx= 1/x
tangent at (x,y) has slope 1/x
eqn of tangent is y = mx + c
since the tangent passes through origin, c=0
substitute y = lnx and m= 1/x to above eqn
lnx = 1
x=e
y=lne=1
Answer:
r=4
Step-by-step explanation:
15r-6r=36
9r=36
r=36/9
r=4
Answer:
21; the age of the teacher
Step-by-step explanation:
15+x/2=18
Estimate - I estimated in the 20's because it only averaged up a little bit
Started with 23 and kept going until i got to my answer
21
15+21/2
36/2
18
Please mark brainliest :)
