Which of the code pieces below should replace the underline?public class Test{public static void main(String[] args){Test test =
1 answer:
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Answer:
the rate of heat loss is 2.037152 W
Explanation:
Given data
stainless steel K = 16 W
diameter (d1) = 10 cm
so radius (r1) = 10 /2 = 5 cm = 5 ×
radius (r2) = 0.2 + 5 = 5.2 cm = 5.2 ×
temperature = 25°C
surface heat transfer coefficient = 6 6 W
outside air temperature = 15°C
To find out
the rate of heat loss
Solution
we know current is pass in series from temperature = 25°C to 15°C
first pass through through resistance R1 i.e.
R1 = ( r2 - r1 ) / 4 × r1 × r2 × K
R1 = ( 5.2 - 5 ) / 4
× 5 × 5.2 × 16 ×
R1 = 3.825 ×
same like we calculate for resistance R2 we know i.e.
R2 = 1 / ( h × area )
here area = 4 r2²
area = 4 (5.2 ×
)² = 0.033979
so R2 = 1 / ( h × area ) = 1 / ( 6 × 0.033979 )
R2 = 4.90499
now we calculate the heat flex rate by the initial and final temp and R1 and R2
i.e.
heat loss = T1 -T2 / R1 + R2
heat loss = 25 -15 / 3.825 × + 4.90499
heat loss = 2.037152 W
Answer:
A) 14.75
B) 3.36Kj
C) 2384.2k
D) 117.6kW
E) 57.69%
Explanation:
Attached is the full solutions.
Answer:
(a) 53.94%
(b) 26.61%
Explanation:
Change in area will be given by
where
represent change in area R is radius and subscripts O and n represent original and new respectively.
Substituting 10.55/2 for original radius and 7.16/2 for new radius then
(b)
Similarly, percentage elongation will be found by dividing the change in length by the the original length. In this case, rhe original length was 54.5mm and goes to 69 mm so the change in length is given by subtracting the final length from the original length
Percentage elongation is