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vredina [299]
3 years ago
8

Which of the code pieces below should replace the underline?public class Test{public static void main(String[] args){Test test =

new Test();test.setAction(_______);}public void setAction(T1 t){t.m();}}interface T1{public void m();}
Engineering
1 answer:
nikdorinn [45]3 years ago
5 0

Which of the code pieces below should replace the underline?public class Test{public static void main(String[] args){Test test = new Test();test.setAction(_______);}public void setAction(T1 t){t.m();}}interface T1{public void m() is explained below

Explanation:

Update of /cvsroot/pydev/org.python.pydev/src/org/python/pydev/editor/correctionassist

In directory sc8-pr-cvs1.sourceforge.net:/tmp/cvs-serv24839/src/org/python/pydev/editor/correctionassist

Modified Files:

PythonCorrectionProcessor.java  

Log Message:

Index: PythonCorrectionProcessor.java

===================================================================

RCS file: /cvsroot/pydev/org.python.pydev/src/org/python/pydev/editor/correctionassist/PythonCorrectionProcessor.java,v

retrieving revision 1.12

retrieving revision 1.13

diff -C2 -d -r1.12 -r1.13

*** PythonCorrectionProcessor.java 23 Feb 2005 14:29:36 -0000 1.12

--- PythonCorrectionProcessor.java 25 Feb 2005 12:34:28 -0000 1.13

***************

*** 419,423 ****

                 //all that just to change first char to lower case.

                 callName = lowerChar(callName, 0);

!                 if (callName.startsWith("get")){

                     callName = callName.substring(3);

                  callName = lowerChar(callName, 0);

--- 419,423 ----

                 //all that just to change first char to lower case.

                 callName = lowerChar(callName, 0);

!                 if (callName.startsWith("get") && callName.length() > 3){

                     callName = callName.substring(3);

                  callName = lowerChar(callName, 0);

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2 years ago
Write a class named FBoard for playing a game, where player x is trying to get her piece to row 7 and player o is trying to make
OverLord2011 [107]

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7 0
3 years ago
how is friction losses in pipes reduced? a. decrease the pipe diameter b. increase the length of the pipes. c. decrease the leng
Citrus2011 [14]

Friction losses in pipes can be reduced by decreasing the length of the pipes, reducing the surface roughness of the pipes, and increasing the pipe diameter. Thus, options (c),(e), and (f) hold correct answers.

Friction loss is a measure of the amount of energy a piping system loses because flowing fluids meet resistance. As fluids flow through the pipes, they carry energy with them. Unfortunately, whenever there is resistance to the flow rate, it diverts fluids, and energy escapes. These opposing forces result in friction loss in pipes.

Friction loss in pipes can decrease the efficiency of the functions of pipes. These are a few ways by which friction loss in pipes can be reduced and the efficiency of the piping system can be boosted:

  • <u><em>Decrease the length of the pipes</em></u>: By decreasing pipe lengths and avoiding the use of sharp turns, fittings, and tees, whenever possible result in a more natural path for fluids to flow.
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3 0
1 year ago
A battery is connected to a resistor. Increasing the resistance of the resistor will __________. A battery is connected to a res
belka [17]

Answer: the increase in the external resistor will affect and decrease the current in the circuit.

Explanation: A battery has it own internal resistance, r, and given an external resistor of resistance, R, the equation of typical of Ohm's law giving the flow of current is

E = IR + Ir = I(R + r)........(1)

Where IR is the potential difference flowing in the external circuit and Or is the lost voltage due to internal resistance of battery. From (1)

I = E/(R + r)

As R increases, and E, r remain constant, the value (R + r) increases, hence the value of current, I, in the external circuit decreases.

8 0
3 years ago
Calculate the theoretical density of FCC iron (eg. austenitic stainless steel). The lattice parameter for FCC iron is 0.357 nm a
Ann [662]

Answer: 12.4 feet

Explanation:

If there is a smooth transition and there is no change in slopes, energy considerations can be used

The cube has a kinetic energy of

ke = mv^2/2 = 10 lbm * 20^2ft^2/s^2 / 2 = 2000 lbm-ft^2 / s^2

At the highest point when there is a gain in potential energy

pe = mgh = 10 lbm * 32.2 ft/s^2 * h ft = 322 lbm ft^2/s^2

If there is no loss in energies,

pe = ke

322h lbm ft^2/s^2 = 2000 lbm ft^2/s^2

h = 2000 /322 = 6.211 (ft)

= h / sin(30) = 12.4 ft

8 0
3 years ago
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