Ask question

Ask question

All categories

3 years ago

6

A string of ASCII characters has been converted to hexadecimal resulting in the following message: 4A EF 62 73 73 F4 E5 76 E5 Of

the eight bits in each pair of digits, the leftmost bit is a parity bit. (a) Convert the string to the bit form (b) Decode the message (c) Which parity code was used, even or odd?

1 answer:

Dafna11 [192]3 years ago

5 0

Answer:sorry I don’t know

Explanation:

You might be interested in

MITM can present in two forms: eavesdropping and manipulation. Discuss the process involved when an attacker is eavesdropping an

Nikitich [7]

Answer / Explanation:

Eavesdropping attack is also sometimes refereed to as sniffing attack. It is simply the process by which an attacker or hacker tries to penetrate very suddenly into an unaware individuals network or server with the intention to steal information transmitted over the network or server through that computer.

To prevent such attack, there are several mean which include installing network monitoring software to check who else is connected to the network but the most common method of preventing such attack is to encrypt the Hypertext Transfer Protocol (http) and the way to do this is by securing it with a sort of security key.

On installing the security key, the network becomes encrypted and secured such that whatever network transmitted over the network becomes encrypted and unable to read. The protocol then converts to (https).

5 0

3 years ago

7. An energy auditor is part of what career field?

Rashid [163]

An energy auditor is part of power operations

6 0

2 years ago

What is one of the “don’ts” in drawing dimension lines? they should never be labeled they should never be stacked they should ne

Strike441 [17]

Answer:

What is one of the “don’ts” in drawing dimension lines? they should never be labeled they should never be stacked they should never cross each other they should never have only one measurement value

5 0

4 years ago

Read 2 more answers

Find the resultant of two forces 130 N and 110 N respectively, acting at an angle whose tangent

monitta

Answer:

$F_r = 200N$

Explanation:

Given

Let the two forces be

$F_1 = 130N$

$F_2 = 110N$

and

$\tan(\theta) = \frac{12}{5}$

Required

Determine the resultant force

Resultant force (Fr) is calculated using:

$F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)$

This means that we need to first calculate $\cos(\theta)$

Given that:

$\tan(\theta) = \frac{12}{5}$

In trigonometry:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

By comparing the above formula to $\tan(\theta) = \frac{12}{5}$

$Opposite = 12$

$Adjacent = 5$

The hypotenuse is calculated as thus:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 12^2 + 5^2$

$Hypotenuse^2 = 144 + 25$

$Hypotenuse^2 = 169$

$Hypotenuse = \sqrt{169$

$Hypotenuse = 13$

$\cos(\theta)$ is then calculated using:

$\cos(\theta)= \frac{Adjacent}{Hypotenuse}$

$\cos(\theta)= \frac{5}{13}$

Substitute values for $F_1$ , $F_2$ and $cos(\theta)$ in

$F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)$

$F_r^2 = 130^2 + 110^2 + 2*130*110*\frac{5}{13}$

$F_r^2 = 16900 + 12100 + 11000$

$F_r^2 = 40000$

Take square roots of both sides

$F_r = \sqrt{40000$

$F_r = 200N$

<em>Hence, the resultant force is 200N</em>

4 0

3 years ago

What is the greatest speedup (in terms of throughput) possible with pipelining? You do not need to worry about the register timi

RUDIKE [14]

Answer:

The greatest speedup possible with pipelining is 2.5 times

Explanation:

As we know

Span of stage = Maximum span of any span

As stage B has the maximum duration of time, So

Duration of time of each stage = Time duration of Stage B = 8 ns

Now calculate the total time without pipeline = Duration of Stage A + Duration of Stage B + Duration of Stage C + Duration of Stage D = 5 ns + 8 ns + 4 ns + 3 ns = 20 ns

So the greatest speedup can be calculated as follow

Greatest speedup = Total time without pipeline / Duration of time of each stage = 20 ns / 8 ns = 2.5 times

3 0

3 years ago