Answer:
When the renewal period comes around (with respect to the license expiry date).
Explanation:
Answer:
repeated?
Explanation:
not really sure what type of answer choices you have
Answer:
Option D
Explanation:
A post development hydrograph will have lower concentration time and lower infiltration losses and hence sooner peak and higher peak and more runoff or higher area under graph. Therefore, all the answers are correct hence option D
Answer:
Explanation:
Given conditions
1)The stress on the blade is 100 MPa
2)The yield strength of the blade is 175 MPa
3)The Young’s modulus for the blade is 50 GPa
4)The strain contributed by the primary creep regime (not including the initial elastic strain) was 0.25 % or 0.0025 strain, and this strain was realized in the first 4 hours.
5)The temperature of the blade is 800°C.
6)The formula for the creep rate in the steady-state regime is dε /dt = 1 x 10-5 σ4 exp (-2 eV/kT)
where: dε /dt is in cm/cm-hr σ is in MPa T is in Kelvink = 8.62 x 10-5 eV/K
Young Modulus, E = Stress,
/Strain, ∈
initial Strain, ![\epsilon_i = \frac{\sigma}{E}](https://tex.z-dn.net/?f=%5Cepsilon_i%20%3D%20%5Cfrac%7B%5Csigma%7D%7BE%7D)
![\epsilon_i = \frac{100\times 10^{6} Pa}{50\times 10^{9} Pa}](https://tex.z-dn.net/?f=%5Cepsilon_i%20%3D%20%5Cfrac%7B100%5Ctimes%2010%5E%7B6%7D%20Pa%7D%7B50%5Ctimes%2010%5E%7B9%7D%20Pa%7D)
![\epsilon_i = 0.002](https://tex.z-dn.net/?f=%5Cepsilon_i%20%3D%200.002)
creep rate in the steady state
![\frac{\delta \epsilon}{\delta t} = (1 \times {10}^{-5})\sigma^4 exp^(\frac{-2eV}{kT} )](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdelta%20%5Cepsilon%7D%7B%5Cdelta%20t%7D%20%3D%20%281%20%5Ctimes%20%7B10%7D%5E%7B-5%7D%29%5Csigma%5E4%20exp%5E%28%5Cfrac%7B-2eV%7D%7BkT%7D%20%29)
![\frac{\epsilon_{initial} - \epsilon _{primary}}{t_{initial}-t_{final}} = 1 \times 10^{-5}(100)^{4}exp(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )(800+273)K} )](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cepsilon_%7Binitial%7D%20-%20%5Cepsilon%20_%7Bprimary%7D%7D%7Bt_%7Binitial%7D-t_%7Bfinal%7D%7D%20%3D%201%20%5Ctimes%2010%5E%7B-5%7D%28100%29%5E%7B4%7Dexp%28%5Cfrac%7B-2eV%7D%7B8.62%5Ctimes10%5E%7B-5%7D%28%5Cfrac%7BeV%7D%7BK%7D%20%29%28800%2B273%29K%7D%20%29)
but Tinitial = 0
![\epsilon_{initial} - \epsilon _{primary}} = 0.002 - 0.003 = -0.001](https://tex.z-dn.net/?f=%5Cepsilon_%7Binitial%7D%20-%20%5Cepsilon%20_%7Bprimary%7D%7D%20%3D%200.002%20-%200.003%20%3D%20-0.001)
![\frac{-0.001}{-t_{final}} = 1 \times 10^{-5}(100)^{4}\times 10^{(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )1073K} )}](https://tex.z-dn.net/?f=%5Cfrac%7B-0.001%7D%7B-t_%7Bfinal%7D%7D%20%3D%201%20%5Ctimes%2010%5E%7B-5%7D%28100%29%5E%7B4%7D%5Ctimes%2010%5E%7B%28%5Cfrac%7B-2eV%7D%7B8.62%5Ctimes10%5E%7B-5%7D%28%5Cfrac%7BeV%7D%7BK%7D%20%291073K%7D%20%29%7D)
solving the above equation,
we get
Tfinal = 2459.82 hr
Answer:
Increased, 5%
Explanation:
Recent studies conducted on online dating sites established that the response of female users increased by 5% when emotions are in their profiles even as for male users' response also increased by 8%. Another study also revealed that those who have never used online dating sites and/or mobile dating apps believe that people who use dating apps are desperate.