Answer:
0.55 m/s
Explanation:
Parameters given:
Mass of lighter car, m = 1400 kg
Mass of heavier car, M = 1850 kg
Initial speed of lighter car, u = -1.10 m/s (since it's moving to the left)
Initial speed of heavier car, U = 1.5 m/s
Final sped of heavier car, V = 0.25 m/s
Using the principle of conservation of momentum, total initial momentum is equal to total final momentum:
m*u + M*U = m*v + M*V
Inputting the values:
(1400 * -1.1) + (1850 * 1.5) = (1400 * v) + (1850 * 0.25)
-1540 + 2775 = 1400v + 462.5
1235 = 1400v + 462.5
1400v = 772.5
v = 772.5/1400
v = 0.55 m/s
Total distance travelled by the car is 'd'
<span>distance trveled before the brakes were applied = v_o * t </span>
<span>distance travld with brakes = d - v_o*t </span>
<span>applying the formula: v^2 - u^2 = -2 a * s </span>
<span>=> 0 - v_o^2 = -2 * a_x * (d- v_o*t) </span>
<span>=> a_x = (v_o^2)/ ( 2 (d-v_o*t)</span>
Answer:
True
Explanation:
Friction between solids can be most accurately defined as the force that
opposes the sliding motion of two surfaces that are touching each other.
Answer:
It has moved a distance, S = 25.9 m
Explanation:
F = 40 v²........(1)
.........(2)
Equating (1) and (2)
Integrate both sides:
.
20% would be probably right cuz 100% is total and 80+ what gives u 100 which is 20
