I believe that the answer is true!
Answer:
0.546 ohm / μm
Explanation:
Given that :
N = 1.015 * 10^17
Electron mobility, u = 3900
Hole mobility, h = 1900
Ng = 4.42 x10^22
q = 1.6*10^-19
Resistivity = 1/qNu
Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)
= 0.01578880889 ohm /cm
Resistivity of germanium :
R = 1 / 2q * sqrt(Ng) * sqrt(u*h)
R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)
R = 1 /0.0001831
R = 5461.4964 ohm /cm
5461.4964 / 10000
0.546 ohm / μm
Explanation:
r^2= 9×10^9 × 5.87×5.87×10^-16 / 64.9
=47.7× 10^-8
so taking sq. root
r = 6.9 ×10^-4 m
or
r= 6.9×10^ -2 cm
this gives the required seperation
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BUT HEY YALL WE NEED THIS ANSWER ASAP
The answer is 25.37 hope this helps