<h3>given:</h3>

<h3>to find:</h3>
the radius of the given ball (sphere).
<h3>solution:</h3>
![r = \sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
![r = \sqrt[3]{ \frac{3 \times 905}{4\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20905%7D%7B4%5Cpi%7D%20%7D%20)

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ball</u><u> </u><u>is</u><u> </u><u>6</u><u> </u><u>cm</u><u>.</u>
note: refer to the picture I added on how you can change r as the subject of the formula.
y varies inversely with x.
Example:
If we multiply x by 2 we need to divide y by 2 too.
So,
If y = 16 and x = 1/2, find y when x = 32
Lets see, from 1/2 to 32 e need to multiply 1/2 by 64, right? So let's divide 16 by 64.
16/64 = 8/32 = 4/16 = 2/8 = 1/4
So we can say that:
If y = 16 when x = 1/2, y = 1/4 when x = 32.
Answer: the answer is pi (π)
Step-by-step explanation: