All categories

3 years ago

Name the ion and formula for bicarbonate

Chemistry

2 answers:

lutik1710 [3]3 years ago

4 0

H3OC, good luck!!!!!!!!!!!

Romashka [77]3 years ago

3 0

I think it is ... HCO3

You might be interested in

Uranus was the first planet to be discovered using a telescope. true or false

slava [35]

Sir William Herschel announced its discovery on 13 March 1781, expanding the known boundaries of the Solar System for the first time in history and making Uranus the first planet discovered with a telescope.

7 0

4 years ago

Read 2 more answers

when heating copper in the final step, the bright copper color changes to a dull brown. will the percent recovery be too high or

jasenka [17]

<span>When heating copper in the final step, the bright copper color changes to a dull brown. I think this process will make the percent recovery low because a change in color can mean some reacted. Hope this answers the question. Have a nice day.</span>

5 0

3 years ago

Please help on this one?

Bezzdna [24]

Answer:

$\text{C. } _{36}^{85}\text{Kr}$

Explanation:

Your nuclear equation is

$_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} +\, _{x}^{y}\text{X}$

The main point to remember in balancing nuclear equations is that

the sum of the superscripts and must be the same on each side of the equation.
the sum of the subscripts must be the same on each side of the equation.

Then

85 = 0 + y, so y = 85 - 0 = 0

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.

The nuclear equation becomes

$_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} + \, _{36}^{85}\text{Kr}$

4 0

3 years ago

Read 2 more answers

If the pressure on gaseous reactant is increased, the rate of reaction is increased because there is an increase in the

mixer [17]

Answer:

collisions between molecules

8 0

3 years ago

ImTwo substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of sub

kipiarov [429]

Answer:

Specific heat capacity of A is 1.05J/g°C

Explanation:

Hello,

In this question, we have to bodies in contact and there's transfer of energy (heat) between them. The heat loss in one body is equal to the heat gain in another body.

Heat loss in B = Heat gain in A

Data,

Mass of A = 6.44g

Initial temperature of A (T1) = 20.3°C

Mass of B = 25.1g

Initial temperature of B = 52.8°C

Final temperature after equilibrium is achieved (T3) = 46.7°C

Specific heat capacity of A (C1) = 1.17J/g°C

Specific heat capacity of B (C2) = ?

Heat loss in B = Heat gain in A

Q = mc∇T

Q = heat energy

M = mass of substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance

M₂C₂(T₂ - T₃) = M₁C₁(T₃ - T₁)

Substitute the values into the variables and solve for C₁

25.1 × 1.17 × (52.8 - 46.7) = 6.44 × C₁ × (46.7 - 20.3)

179.1387 = 170.016C₁

Divide both sides by 170.016

C₁ = 179.1387 / 170.016

C₁ = 1.05J/g°C

The specific heat capacity of A is 1.05J/g°C

6 0

4 years ago