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3 years ago

How does a filter separate mixtures like sand and water?

Chemistry

1 answer:

Talja [164]3 years ago

8 0

Answer:

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Explanation:

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Help me with this science question for brainiest:)

Katen [24]

Answer:

solid liquid and gas

Explanation:

4 0

3 years ago

Read 2 more answers

A material has a volume of 63.0 cm3 and a mass of 28 grams. What is the density of the material in g/cm3 to the correct number

dimaraw [331]

Answer:

0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

Explanation:

Knowing that:

d = m/V,

where, d is the density of the material (g/cm³).

m is the mass of the material (m = 28 g).

V is the volume of the material (V = 63.0 cm³).

∴ d = m/V = (28 g)/(63.0 cm³) = 0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

7 0

3 years ago

you have two solid substances that look the same. what measurements would you take and what tests would you perform to determine

andreev551 [17]

The easiest way to go about this would be to check out their physical properties. Physical properties are those attributes of a substance or material that can be observed or measured without altering or changing the composition of that material.

So we can check out the following physical properties:

1. Color. Check if there is any difference in color.

2. Weight. If possible, take similar sized pieces of the two and note any difference in weight .

3. Texture. Are they smooth or rough to the touch?

4. Smell or odor. Check out any unique smell.

5. Solubility. Dissolve a bit of each in water and see how soluble each is.

6. Melting point. Carefully heat a piece of it and see if they will melt, and if so at what temperature.

7. Pliability. Can any of them bend, are they flexible?

8. Magnetism. Can the be attracted by a magnet?

9. Bouyancy . Can they float on water?

10. Electrical conductivity. using a battery and small torch bulb, find out if they can conduct an electric current.

These 10 physical tests can help differentiate between the two materials. There are still many more that can be safely carried out.

8 0

3 years ago

How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm

Citrus2011 [14]

We are given:_______________________________________________

Volume of Gas (V) = 2.5L

Pressure (P) = 1.2 atm

Temperature (T) = 25°C OR 25+273 = 298 K

Universal Gravitational Constant (R) = 0.0821

Solving for number of moles:___________________________________

From the Ideal Gas Equation,

PV = nRT

(1.2)(2.5) = n(0.0821)(298) [plugging the given values]

n = [(1.2)(2.5)] / [0.0821*298]

n = 300 / [298*8.21]

n = 0.12 moles

Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C

7 0

3 years ago

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h

statuscvo [17]

Explanation:

First, calculate the moles of $CO_{2}$ using ideal gas equation as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $\frac{mass}{volume}$

Hence, mass of water will be as follows.

Density = $\frac{mass}{volume}$

0.998 g/ml = $\frac{mass}{3.26 ml}$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{3.25 g}{18.02 g/mol}$

= 0.180 mol

Moles of hydrogen = $0.180 \times 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $\frac{mass}{12 g/mol}$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.95 g}{16 g/mol}$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_{3}H_{6}O$ .

Thus, we can conclude that empirical formula of the given compound is $C_{3}H_{6}O$ .

6 0

3 years ago

How does a filter separate mixtures like sand and water?​

How does a filter separate mixtures like sand and water?