Answer:
18 g is the mass produced by 4 g of H₂ and 16 g of O₂
Explanation:
The reaction is:
2H₂ + O₂ → 2H₂O
So, let's find out the limiting reactant as we have both data from the reactants.
Mass / Molar mass = moles
4 g/ 2g/m = 2 moles H₂
16g / 32 g/m = 0.5 moles O₂
2 moles of hydrogen react with 1 mol of oxygen, but I have 0.5, so the O₂ is the limiting.
1 mol of O₂ produces 2 mol of water.
0.5 mol of O₂ produce (0.5 .2)/1 = 1 mol of water.
1 mol of water weighs 18 grams.
Just did this question on Mastering Chem, it's 1
Answer:
There are 23076 peanut M&M's in 53.768 kg of M&M's.
Explanation:
First we <u>convert 53.768 kg into g</u>:
- 53.768 kg * 1000 = 53768 g
Then we <u>divide the total mass of M&M's by the mass of one peanut M&M,</u> in order to calculate the answer:
So there are 23076 peanut M&M's in 53.768 kg of M&M's.
Answer:
Because it goes through the process of sublimation.
Explanation:
