3 years ago

What are the three requirements for an effective collision

1 answer:

7 0

In order to produce an effective collision, reactant particles must possess some minimum amount of energy.

...

Kinetics and Collision Theory.

1. The reactants must collide with each other.

2. The molecules must have sufficient energy to initiate the reaction (called activation energy).

3. The molecules must have the proper orientation.

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zubka84 [21]

Answer:

Explanation:

MnO₂(s) + 4 HCl(aq) = MnCl₂(aq) + 2 H₂O(l) + Cl₂

87 g 22.4 x 10³ mL

volume of given chlorine gas at NTP or at 760 Torr and 273 K

= 175 x ( 273 + 25 ) x 715 / (273 x 760 )

= 179.71 mL

22.4 x 10³ mL of chlorine requires 87 g of MnO₂

179.4 mL of chlorine will require 87 x 179.4 / 22.4 x 10³ g

= 696.77 x 10⁻³ g

= 696.77 mg .

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3 years ago

andrezito [222]

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Helen [10]

Answer: [Ne] 3s¹ sodium electron configuration

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mash [69]

I think the answer is C

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nasty-shy [4]

Calcium is in group 2A because it has two valence electrons and an oxidation state of 2+. Hope this is accurate & helpful! Enjoy your evening.

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2 years ago