Question

SrCl2(aq)+2NaF(aq)⟶SrF2(s)+2NaCl(aq)

Answer 1

Answer:

• 637.636 mL of NaF
• 0.7014 moles of SrF2

Explanation:

$C_{1}V_{1}$ = $C_{2}V_{2}$

Where 1 and 2 represent NaF and SrCl2 respectively; and C and V ae concentration and volume.

0.110 × V1 = 0.420 × 167

V1 = $\frac{70.14}{0.110}$ = 637.636 mL ≈ 0.638 L.

Mole ratio of SrF2:

mole ratio of SrCl2 : SrF2 is 1 : 1 (also, conc × vol = no. of moles )

∴ moles of SrF2 = 0.7014.