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ludmilkaskok [199]
3 years ago
7

SrCl2(aq)+2NaF(aq)⟶SrF2(s)+2NaCl(aq)

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

  • 637.636 mL of NaF
  • 0.7014 moles of SrF2

Explanation:

C_{1}V_{1} = C_{2}V_{2}

Where 1 and 2 represent NaF and SrCl2 respectively; and C and V ae concentration and volume.

0.110 × V1 = 0.420 × 167

<em>V1 = </em>\frac{70.14}{0.110}<em> = 637.636 mL ≈ 0.638 L.</em>

Mole ratio of SrF2:

mole ratio of SrCl2 : SrF2 is 1 : 1 (also, conc × vol = no. of moles )

<em>∴ moles of SrF2 = 0.7014.</em>

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