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MatroZZZ [7]
3 years ago
9

Diethyl ether and butan-1-ol are isomers, and they have similar solubilities in water. their boiling points are very different,

however. explain why these two compounds have similar solubility properties but dramatically different boiling points

Chemistry
1 answer:
Bingel [31]3 years ago
5 0

The structure of diethyl ether and butan-1-ol are shown in the figure.

As shown in the figure the diethyl ether will be able to form hydrogen bond with water and so is butanol, due to presence of highly electro-negative element  (oxygen)

However  a molecule of diethyl ether is not able to form such hydrogen bond with another diethyl ether molecule. Due to this it has lower boiling point

Butanol is able to form hydrogen bond with another butanol molecule due to this it has high boiling point


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7. How many moles of mercury(ii) oxide, hgo, are needed to produce 12. 5 g of oxygen, o2? 2 hgo(s) --->2 hg(l) o2(g)
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Moles are the division of the mass and the molar mass. The moles of mercury (ii) oxide in the decomposition reaction needed to produce oxygen are 0.781 moles.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is a breakdown of the reactant into simpler products. The decomposition of mercury (ii) oxide can be shown as:

2HgO(s) → 2Hg(l) + O₂(g)

From the reaction, it can be said that 2 moles of mercury (ii) oxide decomposes to produce 1 mole of oxygen.

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