Diethyl ether and butan-1-ol are isomers, and they have similar solubilities in water. their boiling points are very different,
however. explain why these two compounds have similar solubility properties but dramatically different boiling points
1 answer:
The structure of diethyl ether and butan-1-ol are shown in the figure.
As shown in the figure the diethyl ether will be able to form hydrogen bond with water and so is butanol, due to presence of highly electro-negative element (oxygen)
However a molecule of diethyl ether is not able to form such hydrogen bond with another diethyl ether molecule. Due to this it has lower boiling point
Butanol is able to form hydrogen bond with another butanol molecule due to this it has high boiling point
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Answer:
Explanation:
This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:
The volume of the gas starts at 250 milliliters and the temperature is 137 °C.
The volume of the gas is increased to 425 milliliters, but the temperature is unknown.
We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.
Now the variable is being multiplied by 250 milliliters. The inverse of multiplication is division. Divide both sides of the equation by 250 mL.
The units of milliliters (mL) cancel.
The temperature changes to <u>232.9 degrees Celsius.</u>
Answer:
The answer to the question is
The rate constant for the reaction is 1.056×10⁻³ M/s
Explanation:
To solve the question, e note that
For a zero order reaction, the rate law is given by
[A] = -k×t + [A]₀
This can be represented by the linear equation y = mx + c
Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀
Therefore the rate constant k which is the gradient is given by
Gradient = where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M
= = -0.001056 M/s = -1.056×10⁻³ M/s
Threfore k = 1.056×10⁻³ M/s