Answer:
Rubidium
Explanation:
Rubidium has atomic number 37 and belong to group one alkali metals and has one valence electron at the outermost shell whiz is 5s1
Answer:
Explained below
Explanation:
The human body has a normal core temperature of around 37°C to 38°C.
Now, if it is heated up to say 39° to 40°C, fatigue will start to set in and the brain begins to tell the muscles to slow down.
If it's now heated to higher temperatures above above 41°C, the body will begin to experience heat exhaustion and therefore will start to shut down.
Due to this process, the body can't even sweat at that stage because blood flow to the skin will stops thereby making the body feel cold and clammy. Thus, chemical processes/reaction in the body will begin to be affected and the cells inside the body will start to deteriorate and thus there is now a huge risk of having multiple organ failure.
Answer:
-177.9 kJ.
Explanation:
Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.
