4) B) Speed = Distance/ time
5) C) By applying second law of newton " F = ma" we say that "15 = 12 × acceleration"
15/12= acceleration
acceleration = 1.25 m/s2
6) D) It will continue to accelerate to the right but at a slower rate because of the small force (F2) being applied from the right.
Answer: See below
Explanation:
Therefore, both cars move with a velocity of 18.099 m/s in the direction of 15.945° downward from the x-axis (east)
Answer:
the Jack speed is greater than the Nas speed
v₁ = 2.08 m / s > v2 = 1.85 m / s
Explanation:
For this exercise we can find the average speed of each of the boys, the average speed is defined as the displacement in the time interval
v = x / t
Jack.
It tells us that it travels x = 15 km in a time of t = 2 h
let's reduce the magnitudes to the SI system
x = 15 km (1000 m / 1 km) = 15 10³ m
t = 2 h (3600 s / 1 h) = 7200 s
let's calculate
v₁ = 15 10³/7200
v₁ = 2.08 m / s
Nas travels a distance of x = 10 km in a time of t = 1.5 h
x = 10 km = 10 10³ m
t = 1.5 h (3600s / 1h) = 5400 s
let's calculate the speed
v2 = 10 10³/5400
v2 = 1.85 m / s
From these results we can see that the Jack speed is greater than the Nas speed
