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allochka39001 [22]
3 years ago
8

Describe two methods by a magnet can be demagnetized​

Physics
2 answers:
Mekhanik [1.2K]3 years ago
8 0

Answer:

Demagnetizing a magnet :

  1. By hitting with a hammer
  2. By heating with a high temperature
  3. By dropping the magnet
leva [86]3 years ago
5 0
Being hit with a hammer
Being dropped
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a bullet of mass 4g when fired with a velocity of 50m/s can enter a wall upto a depth of 10cm how much will be the average resis
jok3333 [9.3K]
Mass, m = 4g = 0.004 kg
Velocity, =  50cm/s = 0.5m/s
Distance, 10cm = 0.1m
The wall would have to resist the energy acquired by the bullet.

Kenetic Energy of bullet = Resistance offered by the wall.

1/2 mv²                        =  Resistance Force * Distance

(1/2) * 0.04 * 0.5 * 0.5 =  F * 0.1

0.5 * 0.04 * 0.5 * 0.5 =  F * 0.1

0.5 * 0.04 * 0.5 * 0.5/0.1 = F

0.05 = F

Therefore, Resistance offered by the wall = 0.05 N
8 0
3 years ago
A 7 kg suitcase and a 12 kg suitcase are dropped from the same second story window at the same time. If there is no wind resista
Natali5045456 [20]

Explanation:

the correct answer is C.

if there is no wind resistance; in vaccum both will hit the ground at the same time.

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4 0
3 years ago
A length of wire is cut into five equal pieces. if each piece has a resistance of 0.45 ω, what was the resistance of the origina
azamat
Calculation, add them. 0.85 x 5 = 4.25 Ω
5 0
3 years ago
A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can
yarga [219]

Answer:

D=792.3\ kg/m^3

Explanation:

<u>Average Density </u>

The density of an object of mass m and volume V is

\displaystyle D=\frac{m}{V}

If we know the density and the volume occupied by the object, the mass can be computed as

m=D.V

The tank can hold 20 L of gasoline when full. Converting to cubic meters

V_g=20*0.001=0.02\ m^3

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

m_g=680*0.02=13.6\ kg

To know the total mass of both, we add the 2.5 kg of the tank

m=m_t+m_g=13.6+2.5=16.1\ kg

The volume of the tank is computed solving for V

\displaystyle V=\frac{m}{D}

\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3

The total volume is

V=V_g+V_t=0.02+3.205\times 10^{-4}=0.0203\ m^3

The average density is

\displaystyle D=\frac{16.1}{0.0203}

\boxed{D=792.3\ kg/m^3}

7 0
3 years ago
3. Identify the structures of the skin by the labels A through G below
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3 years ago
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