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2 years ago

Identify conditions that can contribute to an increase in wind erosion.

Physics

2 answers:

nalin [4]2 years ago

8 0

Lake effect is one condition

Sorry if this didn't help- I'm not quite sure what you're asking.

galben [10]2 years ago

3 0

Answer:
1- Lack of plants
2- Dry conditions

Explanation:
Wind erosion is defined as the removal of the top layer of soil by wind. The wind carries this top layer (grains) and deposits it in other placed.
This leads to the land losing its fertility and thus, leads to erosion.
For wind erosion to occur, the soil has to be dry and lacking plants. This makes the top layer vulnerable and can be carried easily by the wind leading to wind erosion.

Hope this helps :)

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Derive the unit of intensity???

zheka24 [161]

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3 years ago

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At a certain time a particle had a speed of 48 m/s in the positive x direction, and 4.5 s later its speed was 92 m/s in the oppo

larisa86 [58]

Answer:

$-31.1 m/s^2$

Explanation:

The acceleration of an object is the rate of change of velocity of the object.

Mathematically, it is calculated as:

$a=\frac{v-u}{t}$

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

Acceleration is a vector, so it is important to also take into account the direction of the velocity.

For the particle in this problem, we have:

u = +48 m/s is the initial velocity (positive direction)

v = -92 m/s is the final velocity (negative direction)

t = 4.5 s is the time interval

Therefore, the average acceleration is

$a=\frac{v-u}{t}=\frac{-92-(+48)}{4.5}=-31.1 m/s^2$

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3 years ago

In the diagram below, a heavy box is being lifted. What is the function of the pulley in this situation?

zepelin [54]

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2 years ago

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Tamiku [17]

Answer:

Explanation:

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2 years ago

A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electri

Alla [95]

Answer:

$q=1\times10^{-8}C$

Explanation:

Let the charge on the ball bearing is q.

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Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

$F=\frac{KQq}{d^{2}}$

By substituting the values

$0.018=\frac{9\times10^{9}\times20\times10^{-9}q}{0.01^{2}}$

$q=1\times10^{-8}C$

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2 years ago