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Lera25 [3.4K]
3 years ago
5

A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the s

nowball. Both people on the skate. the first person is initially moving forward with speed of 2.5m/s, and the second person is initially at rest. what are the volocities of the two people after the snowball is exchanged? disregard friction between the skates and the ice
Physics
1 answer:
Kobotan [32]3 years ago
6 0
Well, st first we should find <span>initial momentum for the first person represented in the task which definitely must be :
</span>(65+0.045)*2.5
And then we find the final one :  65*x + 0.045*30
Then equate them together : x=2.48 m/s 
So we can get the velocity, which is is 2.48 m/s
In that way, according to the main rules of <span>conservation of momentum you can easily find the solution for the second person.
Regards!</span>
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Answer:

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Explanation:

Given data,

The rock is dropped from a bridge.

The initial velocity of the rock, u = 0

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   Using the first equation of motion

                         v = u + gt

                         v = 0 + 9.8 x 1

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                         v = u + gt

                         v = 0 + 9.8 x 3

                          v = 29.4 m/s

c) The velocity of rock at 5.5 second,

                         v = u + gt

                         v = 0 + 9.8 x 5.5

                         v = 53.9 m/s

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