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____ [38]
3 years ago
13

The molar mass of silver (Ag) is 107.87 g/mol.

Chemistry
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

3.53 g

Explanation:

To convert from atoms to moles, you need to know Avogadro's number.  Avogadro's number (6.022 × 10²³) is how many atoms there are in one mole of a substance.  Use this to convert.

(1.97 × 10²² atoms) ÷ (6.022 × 10²³ atoms/mol) = 0.0327 mol

Now that you have moles, use the molar mass to convert to grams.

(0.0327 mol) × (107.87 g/mol) = 3.53 g

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Answer:

between metal and nonmetal ions

Explanation:

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3 years ago
For the following gases, correct the volumes to the conditions indicated. A.654 cm3 at 6 degrees Celsius and 65.3 kPa to 4 degre
leva [86]

Initial pressure of the gas = 65.3 kPa  

Initial volume of the gas = 654 cm³

Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K

Final pressure of the gas = 108.7 kPa

Final temperature of the gas = 4⁰C = 273 + 4 = 277 K

Using the combined gas law for ideal gases:

P₁V₁/T₁ = P₂V₂/T₂  

where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.

Plugging the given data into the combined gas law we have,

(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)

V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)

V₂ = 390.1 cm³


8 0
3 years ago
Chemistry Questions 3. What is true of a strong acid? A. It ionizes close to 100% in water B. It is a weak electrolyte C. It doe
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Strong acid does not conduct electricity. Question 4} A. H30  Question 5 } B. NaOH + CH3COOH
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What mass of silver nitrate is needed to prepare 100cm3 of silver nitrate solution,
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Hope this helps you.

6 0
3 years ago
A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation
AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ (P+\frac{n^2 a}{v^2} )(v-nb)=nRT

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⇒ P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}

       =\frac{(0.467)^2\times 3.49}{(0.245)^2}

       =73.61-13.05

       =60.56 \ atm

8 0
3 years ago
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