The answer is a compound because it is only a compound that can be broken to elements. for eg. H2o is a compound and be broken to element of 2 molecules of hydrogen and oxygen
Explanation:
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Answer:
pH= 12.7
Explanation:
a)Keep an emergency kit and fresh water in your car in the event of _an unexpected event.
b) pOH= -log[OH-]
pOH= -log[5.00×10^-2]
pOH= 1.3
But pH+pOH= 14
pH= 14-pOH= 14-1.3
pH= 12.7
Answer:
75.15 g/mol
Explanation:
First, let us look at the equation of reaction;
From the balanced equation of reaction, 1 mole of NaOH is required to completely neutralize 1 mole of HAA.
Recall that: mole = molarity x volume.
Therefore, 27.50 mL, 0.120 M NaOH = 0.0275 x 0.120 = 0.0033 moles
0.0033 mole of NaOH will therefore requires 0.0033 moles of HAA for complete neutralization.
In order to find the molar mass of the unknown amino acid, recall that:
<em>mole = mass/molar mass</em>, hence, <em>molar mass = mass/mole</em>.
Therefore, molar mass of HAA = 0.248/0.0033 = 75.15 g/mol
Answer:
H₂SO₄
Explanation:
We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.
Step 1: Calculate the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percent composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the atomic mass of the element
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Divide all the numbers by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
The empirical formula of the compound is H₂SO₄.
