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V125BC [204]
4 years ago
5

Ow many grams of NaOH would be needed to react with 199 g of HCl?

Chemistry
2 answers:
irakobra [83]4 years ago
6 0
NaOH + HCL -> Nacl + H2o

1 gram of Naoh reacts with 1 gram of HCL

so 199 g reacts with 199g
german4 years ago
3 0
0.00155 it wants me to explain in 20 word but id rather not
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Which of the four cars had the least net force applied to it when it was launched down the ramp
castortr0y [4]

The least net force applied : Car 3(12 N)

<h3>Further explanation  </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object  

∑F = m. a  

Car 1 ⇒m=0.5 kg, a=36 m/s²

\tt \sum F=0.5\times 36=18~N

Car 2⇒m=0.8 kg, a=50 m/s²

\tt \sum F=0.8\times 50=40~N

Car 3⇒m=0.6, a=20 m/s²

\tt \sum F=0.6\times 20=12~N

Car 4⇒m=1, a=19~m/s²

\tt \sum=1\times 19=19~N

5 0
3 years ago
What is the mole ratio of NH3 to N2?
Ksenya-84 [330]
To answer this question a balanced chemical equation is necessary. The correct equation is: N2 + 3H2 = 2NH3
From this equation, one mole of nitrogen react with 3 moles of hydrogen to give 2 moles of ammonia.
Therefore, the mole ratio of NH3 to N2 is 2:1
8 0
3 years ago
Which is more reactive oxygen or hydrogen? explain why?
mash [69]

Answer:

Explanation:

Which is more reactive hydrogen or oxygen?

Hydrogen is not particularly reactive. For example, just mixing hydrogen and oxygen gas will not cause a reaction at room temperature, but many metal elements oxidize at least on the surface in air. ... It is combustible because oxygen wants electrons and takes them from hydrogen to form water.

6 0
3 years ago
How many moles of atoms are there in 8.814 ×10^23 atoms Ne?
Katen [24]

Answer:

3

Explanation:

6 0
3 years ago
Read 2 more answers
For many years after they were discovered, it was believed that the noble gases could not form compounds. Now we know that belie
Gala2k [10]

Answer:We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.

 mass of Xenon (Xe) = 5.08 g

 mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g

Determine the number of moles of each of the element in the compound. 

   moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe

  moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F

The empirical formula is therefore,

     Xe(0.0387)F(0.232)

Dividing the numerical coefficient by the lesser number.

    XeF₆

Explanation:

6 0
3 years ago
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