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Nataliya [291]
2 years ago
11

Convert 0.00590 lb/qt to g/gal Please help me i will mark the brainliest!!

Chemistry
1 answer:
Dima020 [189]2 years ago
8 0
According to google, one gallon equals 8.36 pounds. I took 8.36and divided by 0.00590 and got 1416.94915254 So if rounded to the nearest hundreth, 1416.95. I have no idea if I'm right. Sorry I couldn't do more!
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Convert mass to moles for both reactants. (Round to 2 significant figures.)
shepuryov [24]
Mass = mr x moles
Mr of CuCl2 = ( 63.5) + ( 35.5 x 2) = 134.5
2.5 = 134.5 x moles
2.5 / 134.5 = moles
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0.25g of Al
Mr of Al = 27
0.25 = 27 x moles
0.25/ 27 = 0.0093 moles (2sf)

Hope this helps :)
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3 years ago
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What is the ph of a solution of 0.700 m kh2po4, potassium dihydrogen phosphate?
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What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su
anastassius [24]

Answer:

V=27992L=28.00m^3

Explanation:

Hello,

In this case, the combustion of methane is shown below:

CH_4+2O_2\rightarrow CO_2+2H_2O

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

8 0
3 years ago
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