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IRINA_888 [86]
3 years ago
5

The _____ method of pest control combines chemical and non-chemical methods and emphasizes the use of natural toxins.

Chemistry
2 answers:
labwork [276]3 years ago
4 0
The answer to the question stated above is:
Integrated Pest Management is a method of agricultural pest control that combines chemical and non <span>chemical methods and emphasizes the use of natural toxins and effective pesticide.

>>N</span><span>atural toxins in plants can also be isolated and applied to crops like synthetic pesticides.</span>
Goryan [66]3 years ago
3 0
The Integrated Pest Management method of pest control combines chemical and non-chemical methods and emphasizes the use of natural toxins. 
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NEED QUICK
motikmotik

Answer: 2. magnesium

Explanation: correct spelling...?

5 0
2 years ago
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According to Table I, which equation represents a change resulting in the greatest quantity of energy released?
love history [14]
The answer is 3. The releasing of energy means exothermic reaction. So the ΔH should be negative. And the greatest quantity of energy released means that the greatest number. So according to the table I, the answer is 3.
8 0
3 years ago
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What happens if a geologist drips a small amount of vinegar (acetic acid) onto a sample of dolomite?
Lapatulllka [165]
Hydrochloric acid on a rock or mineral and watching for bubbles of carbon dioxide gas to be released. The bubbles signal the presence of carbonate minerals such as calcite and dolomite.
4 0
3 years ago
Determine the number of moles in 4.21 x 10^23 molecules of CaCI2?????
Alla [95]

Explanation:

Given parameters:

Number of molecules = 4.21 x 10²³ molecules

Unknown parameters:

Number of moles

Solution:

A mole can be defined as the amount of a substance that contains the avogadro's number of particles i.e 6.02 x 10²³

  To find the number of moles:

          Number of moles = \frac{number of molecules }{[tex]6.02 x 10^{23}}[/tex]

  Number of moles =  \frac{4.21 x 10[tex]^{23} }{6.02 x 10^{23}}[/tex]

Number of moles of CaCl₂ = 0.699moles

Learn more;

mole calculation brainly.com/question/13064292

#learnwithBrainly

8 0
3 years ago
A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained. How many
beks73 [17]

<u>Answer: </u>

A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained where 3 half-lives have passed

<u>Explanation:</u>

Given, the initial value of the sample, A_0 = 150mg

Final value of the sample or the quantity left, A = 18.75mg

Time = 11.4 days

The amount left after first half life will be ½.

The number of half-life is calculated by the formula

\frac{A}{A_{0}}=\left(\frac{1}{2}\right)^{N}

where N is the no. of half life

Substituting the values,

\frac{18.75}{150}=\left(\frac{1}{2}\right)^{N}

\left(\frac{1}{2}\right)^{3}=\left(\frac{1}{2}\right)^{N}

On equating, we get, N = 3

Therefore, 3 half-lives have passed.

7 0
3 years ago
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