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kifflom [539]
4 years ago
15

Mathematically define heat capacity with equations.

Chemistry
1 answer:
zvonat [6]4 years ago
6 0

Answer:    The amount of energy needed to heat the body by 1 ° C (Q)

Explanation:  The heat capacity or as it is called the thermal mass is the amount of energy needed to heat the body by 1 ° C. When the body is said, it refers to any object in any aggregate state. The energy required for the body to warm up by 1 ° C is expressed in joules, and is obtained when the specific heat of the body multiplies with the body mass and with the change of temperature:

Q = m·c·ΔT

<em>Q - heat capacity</em> (J),

m - mass of the body (g),

c - specific heat of the body (J/g-°C),

ΔT - change in temperature (°C)

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Answer:
I. Changing the pressure:
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Decreasing the temperature: the amount of H₂S(g) will increase.
III. Changing the H₂ concentration:
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Explanation:
Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
I. Changing the pressure:
When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
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II. Changing the temperature
The reaction is endothermic since the sign of ΔH is positive.
So the reaction can be represented as:
CH₄(g) + 2H₂S(g) + heat ⇄ CS₂(g) + 4H₂(g).
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The T is a part of the reactants, increasing the T increases the amount of the reactants. So, the reaction will be shifted to the right to suppress the effect of increasing T and the amount of H₂S(g) will decrease.
Decreasing the temperature:
The T is a part of the reactants, increasing the T decreases the amount of the reactants. So, the reaction will be shifted to the left to suppress the effect of decreasing T and the amount of H₂S(g) will increase.
III. Changing the H₂ concentration:
H₂ is a part of the products.
Increasing the H₂ concentration:
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H₂ is a part of the products, decreasing H₂ decreases the amount of the products. So, the reaction will be shifted to the right to suppress the effect of decreasing H₂ and the amount of H₂S(g) will decrease.
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Answer:

See explanation below

Explanation:

For start, we need some values here to do this exercise.

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R: constant gas. In this case is 8.3145 J/mol K

T1 and T2: temperature of the substance.

In order to calculate the normal boiling point, we will assign that value to T2, and the pressure would be 1 atm or 1.01x10^5 Pa

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-4.281x10^-4 + 1/293.15 = 1/T2

T2 = 1 / 2.9831x10^-3

T2 = 335.22 or 62.07 °C

The real one is 59 °C so, the difference in the result may come with the values of P1 and T1 that may be not accurate.

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musickatia [10]
I'm assuming you need to know the percentage yield of the reaction
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actual yield is 56,9 g
predicted yield is 36,6g ( is the amount that's expected if nothing had got lost)

(56,9 x100)/36,6=
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