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3 years ago

If you can simply pour sand into a cup then why is it not a liquid?

2 answers:

7 0

If you pour sand into a cup(empty) why would it change?
If it had water in it then the sand <span>will sink to the bottom</span>, and not change forms.

sleet_krkn [62]3 years ago

6 0

If you, for example, poured it onto a wide cup with a volume equal to the total volume of the sand particles, the sand would not spread out to fill the container but would bunch up together in the middle.

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A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

3 0

3 years ago

4) (5 points) Given are the magnitudes and orientations (with respect to x-axis) of 3

Kazeer [188]

Expand each vector into their component forms:

$\vec A=(4.5\,\mathrm N)(\cos\theta_A\,\vec\imath+\sin\theta_A\,\vec\jmath)=(2.58\,\vec\imath+3.69\,\vec\jmath)\,\mathrm N$

Similarly,

$\vec B=(-1.23\,\vec\imath+0.860\,\vec\jmath)\,\mathrm N$

$\vec C=(-3.44\,\vec\imath-4.91\,\vec\jmath)\,\mathrm N$

Then assuming the resultant vector $\vec R$ is the sum of these three vectors, we have

$\vec R=\vec A+\vec B+\vec C$

$\vec R=(-2.09\,\vec\imath-0.368\,\vec\jmath)\,\mathrm N$

and so $\vec R$ has magnitude

$\|\vec R\|=\sqrt{(-2.09)^2+(-0.368)^2}\,\mathrm N\approx2.12\,\mathrm N$

and direction $\theta_R$ such that

$\tan\theta_R=\dfrac{-0.368}{-2.09}\implies\theta_R=-170^\circ=190^\circ$

5 0

2 years ago

which theory of plate movements involves magma rising all the way from the lower mantle to spread apart plates

KatRina [158]

<span>Hot plumes is the answer

</span>

6 0

2 years ago

Read 2 more answers

When placed in a ________ solution, a cell will exhibit a net loss of water. the specific process by which the water leaves the

katen-ka-za [31]

The specific process by which the water leaves the cell is called <u>plasmolysis.</u>

<h3>What is plasmolysis?</h3>

Plasmolysis is the process in which the cell loses the water that is present inside it because the environment of the cells produces pressure to build up inside the cell. If a cell is present in a hypertonic solution means that solvent concentration is lower in the surrounding solution, then water comes out of the cell while on the other hand, if a cell is present in a hypotonic solution in which the solvent concentration is higher in the surrounding solution, then water goes inside of the cell. The movement of liquid inside or outside of the cell occurs due to the semi-permeable membrane of the cell.

So we can conclude that the specific process by which the water leaves the cell is called <u>plasmolysis.</u>

Learn more about cell here: brainly.com/question/13123319

#SPJ1

7 0

1 year ago

The electric field of a charge is defined by the force on: An electron A probe charge A proton. A source charge.

Alina [70]

Answer:

A probe charge

Explanation:

As we know that electric field intensity is the force experienced by the probe charge which is placed in the electric field region

Here we can say it as

$E = \frac{F}{q}$

so here that probe charge should be very small so that it will not disturb the electric field in the space.

If the probe charge is of large magnitude then the field will get disturbed and the intensity which is to be measured is different from its actual value.

Also the sign of the probe charge is taken to be positive.

so correct answer here will be

A probe charge

7 0

2 years ago