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NeX [460]
3 years ago
11

Select the correct answer.

Physics
2 answers:
jek_recluse [69]3 years ago
7 0

I think the answer is the kinetic energy decreases

Could you put me as brainliest?

zhuklara [117]3 years ago
5 0
I think A the kinetic energy increases
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Which of these would best describe the outcome of increasing the kinetic energy of the molecules in the above picture? A) The te
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Answer: Option (A) is the correct answer.

Explanation:

Relation between kinetic energy and temperature is as follows.

                K.E \propto \frac{3}{2}kT

As, kinetic energy is directly proportional to temperature. So, when there will be increase in temperature then there will also occur increase in kinetic energy of the particles of a substance.

And, when gas particles move slowly then it means kinetic energy of gas particles is very low. It also implies that temperature is low.

Thus, we can conclude that temperature will increase best describes the outcome of increasing the kinetic energy of the molecules in the above picture.

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3 years ago
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When all the spheres on earth interact, that is known as _______
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Answer:

interactions?

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Explanation:

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What is the reaction force if a girl pulls on a cow?
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Answer : B) The cow pulls back on the girl.

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A man weighing 700 NN and a woman weighing 440 NN have the same momentum. What is the ratio of the man's kinetic energy KmKmK_m
Eduardwww [97]

Answer:

The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

Explanation:

Given;

weight of the man, W = 700 N

Weight of the woman, W = 440 N

momentum is given by;

P = mv\\\\v = \frac{P}{m}

Kinetic energy of the man;

K_m = \frac{1}{2}m_m(\frac{P_m}{m_m})^2  \\\\K_m = \frac{P_m^2}{2m_m}

Momentum of the man is calculated as;

P_m^2 = 2m_mK_m

The kinetic energy of the woman is given by;

K_w = \frac{P_w^2}{2m_w}

The momentum of the woman is given;

P_w^2 = 2m_wK_w

Since, momentum of the man = momentum of the woman

P_m^2 = P_w^2

2m_mK_m = 2m_wK_w\\\\\frac{K_m}{K_w} = \frac{2m_w}{2m_m}\\\\\frac{K_m}{K_w} = \frac{m_w}{m_m}

mass of the mas = 700 / 9.8 = 71.429

mass of the woman is = 440 / 9.8 = 44.898

\frac{K_m}{K_w} = \frac{44.898}{71.429}\\\\\frac{K_m}{K_w} =0.629

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

3 0
3 years ago
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