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pav-90 [236]
3 years ago
11

How the periodic table is arranged, who arranged it, and the names of the groups of

Physics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

Mendeleev Arranged it, It was arranged so that elements with the most similar properties were placed in the same group.  and the names on the groups are groups 1, 2, and 12–18. These elements are representative metals, metalloids, and nonmetals. Hope this helped

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Hii can someone please doo this! 50 pointss.
andrey2020 [161]

Answer:

The periodic table illustrate some of the elements from Hydrogen to Calcium

8 0
3 years ago
A 300-W computer (including the monitor) is turned on for 8.0 hours per day. If electricity costs 15¢ per kWh, how much does it
Greeley [361]

Answer:

Cost per year = $131.4

Explanation:

We are given;

Power rating of computer with monitor;P = 300 W = 0.3 KW

Cost of power per KWh = 15 cents = $0.15

Time used per day by the computer with monitor = 8 hours

Thus; amount of power consumed per 8 hours each day = 0.3 × 8 = 2.4 KWh per day

Thus, for 365 days in a year, total amount amount of power = 2.4 × 365 = 876 KWh

Now, since cost of power per KWh is $0.15, then cost for 365 days would be;

876 × 0.15 = $131.4

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3 years ago
HELP!! ILL GIVE BRAINLIEST As we've learned so far, the popular model of the solar system shifted over
Mademuasel [1]

Answer:

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4 0
3 years ago
Suppose that the acceleration of a model rocket is proportional to the difference between 100 ft/sec and the rocket's velocity.
sp2606 [1]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 80 ft/s

acceleration, a = 150 ft/s²

Let the time taken is t.

v = u + at

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3 0
3 years ago
300 grams of ethanol is heated with 14640 Joules of energy to reach a final temperature of 30 °C. What was the initial temperatu
levacccp [35]

Answer:

10 °C

Explanation:

Applying

q = cm(t₂-t₁)............... Equation 2

Where q = heat energy, c = specific heat of ethanol, m = mass of ethanol, t₁ = initial temperature, t₂ = Final temperature.

Given: c = 2.44 J/g.°C,  m = 300 g, q = 14640 J, t₂ = 30°C

Substitute into equation 2 and solve for t₁

14640 = 2.44×300(30-t₁)

14640 = 732(30-t₁)

732(30-t₁) = 14640

(30-t₁)  = 14640/732

(30-t₁)  = 20

t₁ = 30-20

t₁ = 10 °C

6 0
3 years ago
Read 2 more answers
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