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3 years ago

A teacher sends her students on a treasure hunt. She gives the following instructions:

Physics

1 answer:

Norma-Jean [14]3 years ago

7 0

Answer:

D) Joe need to walk 481 m in a direction 40.9° north of east

Explanation:

Given:

1. Walk 300 m north

2. Walk 400 m northwest

3. Walk 700 m east-southeast and the treasure is buried there

Taking north as positive y axis and east as positive x axis.

Resolving their positions into x and y vector components.

1. d1 = 300j

2. d2 = -400cos45i + 400sin45j

3 d3 = 700cos22.5i - 700sin22.5j

Resultant position.

d = d1+d2+d3

d = (-400cos45 + 700cos22.5)i + (300+400sin45-700sin22.5)j

d = (363.873)i + (314.964)j

D = √( (363.873)^2 + (314.964)^2)

D =481.25m ~= 481m

Angle = taninverse (314.964/363.873)

Angle = 40.9°

Since the x and y components are both positive, it implies that their position is north of east

Therefore, Joe need to walk 481 m in a direction 40.9° north of east

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4 years ago

If four students separately measure the density of a rock, and they all have very low percent

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Answer:

Their measured results are closer to the exact or true value. Hence, their measured value is considered to be more accurate.

Explanation:

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3 years ago

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3 years ago

A force has both______ and _______. Question 1 options: Speed and impact Magnitude and direction Motion and speed Direction and

Travka [436]

Answer:

magnitude

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2 years ago

algunas fabricas de balones de futbol ubicadas en la costa inflan los balones que van a ser vendidos en ciudades como pasto,tunj

solmaris [256]

Answer:

Debido al cambio de volumen del gas dentro de la bola cuando se somete a una disminución de la presión y un aumento de la temperatura de la atmósfera.

Explanation:

La ubicación de las fábricas que fabrican las bolas que se encuentra en la costa como se indica en la pregunta es a baja altitud y una región más fría donde la presión atmosférica es más alta

Por lo tanto, la presión en la costa = p₁

La temperatura en la costa = T₁

El volumen de la pelota en la costa = V₁

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La presión en la ciudad = p₂ <p₁

La temperatura en la ciudad = T₂> T₁

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$\dfrac{p_1 \times V_1}{T_1} = \dfrac{p_2 \times V_2}{T_2}$

Allí el volumen de la pelota en la ciudad estará dado por la relación;

$V_2 = V_1 \times \dfrac{p_1 }{P_2} \times \dfrac{ T_2}{T_1 }$

Dado que p₁> p₂ y T₂> T₁, entonces p₁/p₂> 1 y T₂/T₁> 1 y tenemos;

V₂ = V₁ × p₁/p₂ × T₂/T₁ = V₁ × X, donde X = p₁/p₂ × T₂/T₁> 1

V₂ = V₁ × X (> 1)

Por lo tanto, V₂> V₁ y el volumen ocupado por el gas aumenta cuando la pelota llega a la ciudad y la pelota está más firme.

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3 years ago