Find the number of kilowatt-hours of energy used when a 110-watt light bulb burns for 215 hours.

1 answer:

5 0

We determine the kilowatt-hour by multiplying the energy in kilowatt and the time in hours. We do as follows:

kWh = 110 W ( 1 kW / 1000 W ) (215 hrs )
kWh = 23.65 kWh

Hope this answers the question. Have a nice day.

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A cylinder has a volume of 175 cubic units and a height of 7 units. The diameter of the cylinder is

VashaNatasha [74]

The answer is <span>10 units
</span>
The diameter of the cylinder (d) is the twice of its radius (r): d = 2r

The volume (V) of the cylinder with radius r and height h is:
V = π r² h

We have:
d = 2r
r = ?
h = 7
π = 3.14
V = 175π

175π = π * r² * 7
175 = r² * 7
r² = 175/7
r² = 25
r = √25
r = 5

d = 2r
d = 2 * 5
d = 10

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3 years ago

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Goran is on his way home in his car. He has driven 12 miles so far, which is two-thirds of the way home. What is the total lengt

Vinil7 [7]

Answer:

2/3 = 12

12/2 = 1/3

1/3 = 6

3/3 = 3x6

Whole drive = 18miles

Hopefully this helps