Answer:
We need 8.11 grams of glucose for this solution
Explanation:
Step 1: Data given
Molarity of the glucose solution = 0.300 M
Total volume = 0.150 L
The molecular weight of glucose = 180.16 g/mol
Step 2: Calculate moles of glucose in the solution
Moles glucose = molarity solution * volume
Moles glucose = 0.300 M * 0.150 L
Moles glucose = 0.045 moles glucose
Step 3: Calculate mass of glucose
MAss glucose = moles glucose* molecular weight of glucose
MAss glucose = 0.045 moles * 180.16 g/mol
MAss glucose = 8.11 grams
We need 8.11 grams of glucose for this solution
Answer:
A. Kilo , K, multiplication by 1000
B. Centi, c
C. Deci, d
D. Mili, m
E. Mega, M
F. Micro, u
Answer:
c
Explanation:
it is corundum now please follow me
the answer is 15.
4+4+4+1 =13 then u add the 2 outside the bracket which will give u 15