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3 years ago

How many atoms are in 16.1 G Sr

Chemistry

1 answer:

marysya [2.9K]3 years ago

4 0

Answer: There are $1.11\times 10^{23}$ atoms of Sr

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{16.1g}{87.6g/mol}=0.184moles$

1 mole of Sr contains = $6.023\times 10^{23}$ atoms of Sr

Thus 0.184 moles of Sr contains = $\frac{6.023\times 10^{23}}{1}\times 0.184=1.11\times 10^{23}$ atoms of Sr

Thus there are $1.11\times 10^{23}$ atoms of Sr

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There is some info missing. I looked at the question online.

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