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Natasha_Volkova [10]
2 years ago
5

How many atoms are in 16.1 G Sr

Chemistry
1 answer:
marysya [2.9K]2 years ago
4 0

Answer: There are 1.11\times 10^{23} atoms of Sr

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{16.1g}{87.6g/mol}=0.184moles

1 mole of Sr contains =  6.023\times 10^{23} atoms of Sr

Thus 0.184 moles of Sr contains =  \frac{6.023\times 10^{23}}{1}\times 0.184=1.11\times 10^{23} atoms of Sr

Thus there are 1.11\times 10^{23} atoms of Sr

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3 years ago
What is the final pressure of a system (atm) that has the volume increased from 0.75 l to 1.1 l with an initial pressure of 1.25
lana66690 [7]
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3 0
3 years ago
Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n
insens350 [35]
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7 0
3 years ago
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

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Reduction half equation:

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E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
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