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Natasha_Volkova [10]
3 years ago
5

How many atoms are in 16.1 G Sr

Chemistry
1 answer:
marysya [2.9K]3 years ago
4 0

Answer: There are 1.11\times 10^{23} atoms of Sr

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{16.1g}{87.6g/mol}=0.184moles

1 mole of Sr contains =  6.023\times 10^{23} atoms of Sr

Thus 0.184 moles of Sr contains =  \frac{6.023\times 10^{23}}{1}\times 0.184=1.11\times 10^{23} atoms of Sr

Thus there are 1.11\times 10^{23} atoms of Sr

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<h2>Hello!</h2>

The answer is:

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The Ideal Gas Law equation is equal to:

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So, from the statement we know that:

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