About one kilogram of coffee beans is required
Answer:
Mass = 18 g
Explanation:
Given data:
Number of molecules of Dicarbon hexahydride = 3.58 × 10²³ molecules
Mass of Dicarbon hexahydride = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
3.58 × 10²³ molecules × 1 mol / 6.022 × 10²³ molecules
0.6 mol
Mass of Dicarbon hexahydride:
Mass = number of moles × molar mass
Mass = 0.6 mol × 30 g/mol
Mass = 18 g
Answer:
a) 8×10²³ molecules of N2
Explanation:
Let us consider the same temperature and pressure of both sample are standard temperature and pressure.
Standard temperature = 273.15 K
Standard pressure = 1 atm
Number of moles of CO₂ = 0.107 mol
Volume of CO₂ = ?
Solution:
PV = nRT
R = general gas constant = 0.0821 atm.L /mol.K
1 atm × V = 0.107 mol × 0.0821 atm.L /mol.K × 273.15 K
1 atm × V = 2.4 atm.L
V = 2.4 atm.L/1 atm
V = 2.4 L
Volume of N₂:
Number of moles of N₂:
1 mole = 6.022 ×10²³ molecules
8×10²³ molecules × 1 mol / 6.022 ×10²³ molecules
1.33 mol
PV = nRT
R = general gas constant = 0.0821 atm.L /mol.K
1 atm × V = 1.33 mol × 0.0821 atm.L /mol.K × 273.15 K
1 atm × V = 29.83 atm.L
V = 29.83 atm.L/1 atm
V = 29.83 L
<span>In general,atomic size increases from top to bottom within a group and decreases from left to right across a period</span>
