I hope I am correct my Science teacher said this was the answer to your question
We have: K.E. = 1/2 mv²
Here: m = 50 g = 0.05 Kg
v = 4 m/s
Substitute their values,
K.E. = 1/2 * 0.05 * 4²
K.E. = 1/2 * 0.05 * 16
K.E. = 0.4 J
In short, Your Answer would be 0.4 Joules
Hope this helps!
Answer:
Explanation:
100 persent transmission implies that the T=1
Therefore using the previous result we have


The depth of the well for 100% transmission should be

Answer:
The spring constant of the spring is 47.62 N/m
Explanation:
Given that,
Mass that is attached with the spring, m = 29 g = 0.029 kg
The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,

f = 6.45 Hz
The frequency of oscillator is given by :

k is the spring constant


k = 47.62 N/m
So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.