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pshichka [43]
3 years ago
8

Collisions tend to happen when one driver is going faster or slower than other cars on the road

Physics
2 answers:
iogann1982 [59]3 years ago
8 0
Faster or about the same speed.
Triss [41]3 years ago
6 0
Collisions tend to happen when one driver is going faster on the road. Because the increase in velocity creates a higher chance of accidents. The faster you go the easier it is to have an accident.
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How do prokaryotes differ from eukaryotes ?
Ber [7]
I hope I am correct my Science teacher said this was the answer to your question

5 0
3 years ago
PLEASE HELPPP 100 POINTS HURRY !!!!Which diagram best illustrates the magnetic field of a bar magnet? A bar magnet with a north
Serggg [28]

I think this is right I hope this is right for you

7 0
3 years ago
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A 50g man is walking at a speed of 4m/s. what is the kinetic energy of the walker?
Phantasy [73]
We have: K.E. = 1/2 mv²
Here: m = 50 g = 0.05 Kg
v = 4 m/s

Substitute their values, 
K.E. = 1/2 * 0.05 * 4²
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Hope this helps!
4 0
4 years ago
(b) Show that for certain incident energies there is 100 percent transmission. Suppose that we model an atom as a one-dimensiona
bixtya [17]

Answer:

Explanation:

100 persent transmission implies that the T=1

Therefore using the previous result we have

1+\frac{\sin^2\sqrt{\frac{2m}{\hbar^2}(E+V_0)}a}{4\frac{E}{V_0}\frac{(E+V_0)}{V_0}}=1


\sin\sqrt{\frac{2m}{\hbar^2}(E+V_0)}a=0\Rightarrow \sqrt{\frac{2m}{\hbar^2}(E+V_0)}=0\Rightarrow E=-V_0


The depth of the well for 100% transmission should be

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7 0
3 years ago
When a mass of 29 g is attached to a certain spring, it makes 20 complete vibrations in 3.1 s. What is the spring constant of th
never [62]

Answer:

The spring constant of the spring is 47.62 N/m

Explanation:

Given that,

Mass that is attached with the spring, m = 29 g = 0.029 kg

The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,

f=\dfrac{20}{3.1}

f = 6.45 Hz

The frequency of oscillator is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

k is the spring constant

k=4\pi^2f^2m

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k = 47.62 N/m

So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.

4 0
3 years ago
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