The <u>frequency</u> of emitted light is directly proportional to the energy between the two orbits and this determines the color of the light.
<h3>What is light?</h3>
Light can be defined as a form of electromagnetic waves that does not require any medium for its propagation. This ultimately implies that, light is a form of wave that is generally referred to as a visual signal because it can be seen with the eyes.
According to the model of light wave, the <u>frequency</u> of emitted light is directly proportional to the energy between the two orbits and this determines the color of the light.
<em>In conlcusion, the </em><u><em>frequency</em></u><em> of emitted </em><em>light</em><em> is highly dependent on the </em><em>energy</em><em> between the two (2) </em><em>orbits</em><em>.</em>
Read more on energy here: brainly.com/question/1242059
Explanation:
What is IEEE 802.11?
IEEE 802.11 is a set of WLAN standards for communication developed by the Institute for Electrical and Electronics Engineers (IEEE) and is unarguably most widely used WLAN technology.
Features: IEEE 802.11a
- The operating frequency band is 5 GHz.
- The maximum theoretical data rate is 54 Mbps, the typical throughput is around 25 Mbps and minimum data rate is 6 Mbps.
- It can support 64 users per access point.
Features: IEEE 802.11b
- The operating frequency band is 2.4 GHz.
- The maximum theoretical data rate is 11 Mbps but typical throughput is around 6 Mbps and minimum data rate is 1 Mbps.
- It can support 32 users per access point.
Wireless Coverage IEEE 802.11a Vs IEEE 802.11b:
- Signal coverage is one of the most important factors among users.
- The transmission range of IEEE 802.11a is not greater than 100 ft in indoor setting whereas IEEE 802.11b has a superior performance in this regard with transmission range up to 150 ft in indoor setting.
- The data rate has a direct relation with the access point coverage area, a higher data rate means less coverage area and a lower data rate results in increased coverage.
Answer:
Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t ′ )
2
t
′
=3s
Total time= 3+2= 5s
Explanation:
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