For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).
Thus, there are 16 possible sums when three six-sided dice are rolled.
Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.
The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.
That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
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Answer:
x= −3 and y= 4
not sure if this is what your looking for tho
Step-by-step explanation:
Answer:43.1
Step-by-step explanation:delta math
Answer:
x = 35
Step-by-step explanation:
First you have to isolate x. In order to do this, you have to multiply each side by 5.
This leaves you with x = 35.
240mg•3=720mg of sodium per 1 whole pickle
325mg•2=650mg of sodiun per 1 whole pickle.