The initial velocity is 
Explanation:
The motion of the ball is a projectile motion, therefore it consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction
In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by

where
is the horizontal velocity
t is the time of flight
Here we have:
t = 0.45 s
x = 3.0 m
And so solving for
, we find

And since the ball was initially projected horizontally, this is also the initial velocity.
Learn more about projectile motion:
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You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.
So there are different ways this could be solved. I'll do try to explain it the way I was taught...
Simon is riding his bike at 12 km/hr relative to the sidewalk, away from where Keesha is.
Simon throws the ball at Keesha, at 5 km/hr.
Keesha sees the ball approaching her at (12-5) = 7 km/hr relative to the ground to her.
Therefore the answer is: 7 km/hr
Wavelength = 1/frequency thus wavelength =1/30000
Answer: A.). Be equal to the time the ball hits the group
Explanation: